Solution.
Mass of gyroscope, M= 0.2 Kg
Radius of gyration of gyroscope, Rg= 50 mm
Moment of inertia, I of the gyroscope = MRg2 = 0.2* (0.05)2 =0.00005 Kgm2
Radius of circular path=R
speed of submarine, v= 36 km/hr
Angular velocity of single rotor gyroscope, w1= 500 rad/s
Angular velocity of submarine, w2= 10/R rad/s
Gyroscopic torque, Tg= Iw1w2 = F.d
0.0005*50* 10/R = 1.2 * 0.15
R= 13.88 m ........ (a)
b) To find out the direction of the spin look at the following figure.
When rotor is viewed from the starboard side, it rotates in anticlockwise direction. While the submarine takes a right turn. Due to this we get an active gyroscopic couple as shown and in turn, a reactive gyroscopic couple which actually move the submarine.
Reactive gyroscopic couple is upwards and when we use right hand thumb rule, we get that starboard moves downwards and port moves upwards which means a rolling movement of the submarine.
step by step explanation please Working from first principles show that the gyroscopic torque Ta generated by a body of polar moment of inertia I spinning about one axis at an angular velocity an...