Question

Show work please.

can be used for produced from an IR device. The indirect is method is preferable because the thermocouples are eventually destroyed by the solution. Consider the following 10 measurements: 931 919 943 332 935 x (Round your answers to 3 decimal places) b, Test tor sigificance od regression using a = 0.05 and calculate R2 Calculate 6 (Round your answer to 2 decimal places) RP. (c) Test the %(Round your answer to 2 decimal places.) (Round your answers to 3 decimal places.) Calculate s there evidence to support a claim that both devices produce equivalent temperature measurements?

Answer 1

r work

> x=c(920,935,916,920,940,933,925,940,933,927)
> y=c(917,934,924,921,945,931,919,943,932,935)
> a=lm(y~x)
> a

Call:
lm(formula = y ~ x)

Coefficients:
(Intercept) x
10.7575 0.9897

> anova(a)
Analysis of Variance Table

Response: y
Df Sum Sq Mean Sq F value Pr(>F)
x 1 647.37 647.37 25.956 0.000936 ***
Residuals 8 199.53 24.94   
---
Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1
> summary(a)

Call:
lm(formula = y ~ x)

Residuals:
Min 1Q Median 3Q Max
-7.240 -2.908 -1.214 3.414 6.780

Coefficients:
Estimate Std. Error t value Pr(>|t|)
(Intercept) 10.7575 180.4583 0.060 0.953927
x 0.9897 0.1943 5.095 0.000936 ***
---
Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1

Residual standard error: 4.994 on 8 degrees of freedom
Multiple R-squared: 0.7644,   Adjusted R-squared: 0.7349
F-statistic: 25.96 on 1 and 8 DF, p-value: 0.000936

>

answers:

a)

10.757 + 0.9902. У

b)

fo = 25.96

yes the simple linear regression model is significant.as p value is

0.000936

R- 0.76

c)

to = 5.095

YES there is evidence that both the devices produces equivalent temperature measurements.