Question

We can play a variation of a child's game called "What am 12" that I will call "Where am 1? (a) I am a square. The intersection of my two diagonals lies at the point (4, 4), and the length of each of my sides is 8. My sides form horizontal and vertical lines. Where am I? Order your answers from smallest to largest x, then from smallest to largest y.) x, y) (x, y)s x, y) (x, y) (b) I am an isosceles triangle. The midpoint of my non-congruent side is the point (7, -4). This side is a horizontal line with a length of 4 and my vertex opposite this side is at the point (7,-11). Oh, I almost forgot to tell you. I am upside down. Where am I? (Find the coordinates of each base vertex.) (x, y)s x, V) с 1 am a right isosceles triangle I have an area of 50 square units. The coordinates the vertex at which the two congruent sides meet is (smaller x-value) (larger x-value) my side torm horizontal and O an vertical lines. Do you have enough information to determine the coordinates of my two possible remaining vertices? Yes No If so, find them. (If there is not enough information enter NOT ENOUGH.) (x, y) (x, y) = ) (vertical side) X (horizontal side)

Answer 1