a) heat lost by conduction = kAdT/dx
where K = thermal conductivity of pipe
A = cross sectional area
dT/dx = thermal gradient
= 0.045*pi*0.05^2 * (90 -40) / 0.2
= 0.088 W
b) heat lost =0.045*pi*0.05^2 * (90 -40) / 0.1
= 0.17 W
Exercise 1.17 A pipe with a diameter of 10 cm is surrounded by a sheet-metal clad insulation of 20 cm mineral wool (A = 0,045 W/m K). a) What is the heat loss per meter of pipe when the pipe is 9...
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