Question


STATS03-SPI 9.01 PRİCompatibility Model . Word SİGN PAGE LACUT . REFERENCES MAR NGS REV EV VIEW DESIGN uAruT a-E , . tE· u ㅡ


media%2Fa76%2Fa76ee987-b39c-4db8-adc4-2c
0 0
Add a comment Improve this question Transcribed image text
Answer #1

a) Scatter plot of Power consumption vs Avg Product Purity is shown below. The relationship looks non-linear from the plot below.

95 94 93 92 90 89 o 88 86 85 50 100 150 250 300 350 X1 (AvgProdPurity)

b) Correlation(Y, X1) = 0.0488

Correlation(Y, X2) = -0.0092

Looking at the low correlation coefficient in either case, both the independent variables show a weak linear relationship with the dependent variable.

c) Carrying out regression between Y, X1 and X2 in excel (go to Data tab-> Data Analysis -> Regression) we get the following output:

Regression Statistics
Multiple R 0.050571764
R Square 0.002557503
Adjusted R Square -0.219096385
Standard Error 27.16048318
Observations 12
Coefficients Standard Error t Stat P-value Lower 95% Upper 95%
Intercept 235.4441624 337.9871826 0.696606778 0.503641767 -529.1359637 1000.024288
X1 (AvgProdPurity) 0.540644691 3.619346314 0.149376336 0.884550424 -7.646885498 8.72817488
X2 (TonsProduced) -0.050252565 1.27775449 -0.039328811 0.969486837 -2.940734037 2.840228907

Hence, least squares regression line: Y = 235.44 + 0.541 * X1 - 0.0503 * X2

d) Coefficient of purity = 0.541,which is +ve suggesting a positive linear relationship with power consumed. However, the high p-value of 0.8845 suggests this correlation is weak

Coefficient of purity = -0.0503,which is +ve suggesting a negative linear relationship with power consumed. However, the high p-value of 0.9695 suggests this correlation is again very weak

e) Coefficient of determination, R-squared = 0.00256

=> only 0.256% of the variation in Y (Power consumption) is explained by the variation in X1 and X2

f) Given p-values for both avg product purity (X1) and tons of product produced (X2) are high (>>0.05), they are not useful predictors of power consumption

g) The p-value of both the coefficients is extremely high (0.8845 and 0.9695), much higher than 0.01, suggesting it is a very poor linear regression model where both the predictor variables fail in predicting the dependent variable at any significant level of accuracy.

h) For X1 = 90% and X2 = 98, we have

Y = 235.44 + 0.541 * 90 - 0.0503 * 98 = 279.2 (1000 kWh)

i) The assumption of the fitted model is that the errors in prediction are normally distributed, which doesn't look like the case from the prediction errors (Y_predicted - Y_observed) plotted below, which is far from normal, thus violating the most basic premise of regression.

Error(Pred) 50 40 漠) 20 10 9 10 12 4 10 20 漠) 4

Add a comment
Know the answer?
Add Answer to:
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT