Q2- second option is correct
Q3-
The problen can be solved from strain compatibility
Let total cross sectional area be A
Area of gravel=0.45A
Area of sand=0.33A
Area of cement=0.22A
Let total deformation be d and initial length be L
Strain of all materials is equal and equal to k
Stress in gravel=k*Eg
Stress in sand=k*Es
Stress in cement=k*Ec
Let equivalent Modulus of elasticity be E
k*E*A=k*Eg*0.45A+k*Es*0.33A+k*Ec*0.22A
E=0.45*150+0.33*55+0.22*13000=2945 MPa
This is the required answer
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