Question

D. Since a frequency response as seen in C. is clearly unacceptable, the capacitor Cl is used to decrease the feedback signal
Problem1 Hi-fi audio amplifiers are usually built as discrete difference amplifiers with a rel- atively large gain (near 55dB
D. Since a frequency response as seen in C. is clearly unacceptable, the capacitor Cl is used to decrease the feedback signal at higher frequencies. Components are chosen as follows: R1-320k2, R2-10k2, C1-4.7nF. The transfer function of the feedback network is therefore 10, 000 Ro GRVoUT() urs) RRC1+RR 15.5330, 000 Determine the combined transfer function IsPx(s)/V(s) when the frequency compensation capacitor CI is installed and determine the poles and zeros (if any) of the new transfer function. [10 points]
Problem1 Hi-fi audio amplifiers are usually built as discrete difference amplifiers with a rel- atively large gain (near 55dB or more) and with built-in feedback that reduces the closed-loop gain to a much smaller value in the range of 30- 35dB. Since loudspeakers predominantly act like a resistor (nominal impedance: 4Ω) with an inductor in series, the feedback network can also be used to improve the frequency response in the audio range up to 20 kHz. In this problem, we are primarily con- cerned with gain and frequency response of the amplifier. Amp Vour(s) R1 : R C1 R2 FeedbackL Network Speaker Impedance GFB(s) Speaker Impedance Discrete operational amplifier Vour(s)1 V(s) Vre(s) Figure 1: Simplified schematic (A) and block diagram representation (B) of a hi-fi ampli- fier output stage with feedback network and loudspeaker impedance. The magnetic force that drives the membrane is proportional to the coil current Isp, and the coil current is therefore the output variable that we are interested in.
0 0
Add a comment Improve this question Transcribed image text
Answer #1

0 ion Th· HEt audio dAptie,ex as usually buit as disect k tes Conpecing the leed bock the clased loop opain coll| be 2educed(-- leed bad (riven 9ap -500 32 abive loo ems axe independent i Psequerc Foom aln dvided os k 노(t) HGRAS) S00 32 500 5-62S 50I (S) RHS 3aom Whts he above ta talculale (Pn (S) 20k - 2N (820k VCS) Cs GFB(PHLS) t(s) SubettoHng the calcola Hon v(S) CS ScD The grven condiMon is not acceptoble G (S) Vtn Cs Scanned with CamScannerVtst ) Vin (S11) うThe feed book loop can be drawn A08 above een on VCS 2BX46ok LsHM T (S) s+s) Scanned wi^500 6 Sol 165000)(Rt6AAuk to5%) z) 6-117 μ V(S) Scanned with CamScanner

Add a comment
Know the answer?
Add Answer to:
D. Since a frequency response as seen in C. is clearly unacceptable, the capacitor Cl is used to decrease the feedback signal at higher frequencies. Components are chosen as follows: R1-320k2, R...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT