Observe that the point (1,1,1) satisfies the equation 2. Although we may not be able to write down a formula for z in terms of x and y there is a function z(x,y) that has continuous partial derivativ...

Question

Question

Observe that the point (1,1,1) satisfies the equation 2. Although we may not be able to write down a formula for z in terms o

math Advanced-Math

Add a comment Improve this question Transcribed image text

Answer 1

Answer #1

Diffeentali ge I o ラース 26-3-3. -55 х. so at (リリ2-1J we get O2. ou 4 . 08 uppose R using (, we get P5 then we az so have a problem Using we get ustra P5 then yt

Add a comment

Answer 2

Similar Homework Help Questions

Observe that the point (1,1,1) satisfies the equation 2. Although we may not be able to write down a formula for z in terms of x and y there is a function z(x,y) that has continuous partial derivativ...

Observe that the point (1,1,1) satisfies the equation 2. Although we may not be able to write down a formula for z in terms of x and y there is a function z(x,y) that has continuous partial derivatives, is defined for (x,y) near (1,1), and for which z(1,1) 1. For this function find the values of the partials дг/дх (1,1) and дг/ду (1,1). Use this to approximate z(1.1 ,9). Finally, find Эгјах (1,1). If we try to do similar calculations...
(1 point) Consider the function defined by ?(?,?)=??(9?2+5?2)?2+?2F(x,y)=xy(9x2+5y2)x2+y2 except at (?,?)=(0,0)(x,y)=(0,0) where ?(0,0)=0F(0,0)=0. Then we have...

(1 point) Consider the function defined by ?(?,?)=??(9?2+5?2)?2+?2F(x,y)=xy(9x2+5y2)x2+y2 except at (?,?)=(0,0)(x,y)=(0,0) where ?(0,0)=0F(0,0)=0. Then we have ∂∂?∂?∂?(0,0)=∂∂y∂F∂x(0,0)= ∂∂?∂?∂?(0,0)=∂∂x∂F∂y(0,0)= Note that the answers are different. The existence and continuity of all second partials in a region around a point guarantees the equality of the two mixed second derivatives at the point. In the above case, continuity fails at (0,0)(0,0). (1 point) Consider the function defined by F(x, y) = xy(9x2 + 5y2) x2 + y2 except at (x, y) = (0,0)...
4. Suppose you are given an equation of the form F(x, y,z) 0. Then we can say that each of the variables is defined implicitly as a function of the others. 2 a) If F and z(x, y) are both assumed to b...

4. Suppose you are given an equation of the form F(x, y,z) 0. Then we can say that each of the variables is defined implicitly as a function of the others. 2 a) If F and z(x, y) are both assumed to be differentiable, fnd in terms of partial derivatives of F. b) Under similar assumptions on the other variables, find 4. Suppose you are given an equation of the form F(x, y,z) 0. Then we can say that each...

(1 point) f(az +by), ie the RHS is a inear function of z and y We...

(1 point) f(az +by), ie the RHS is a inear function of z and y We wil use the substtution oaz+ by to find an impict general solution In case an equation is in the form +yo sove the initial value problem. The right hand side of the following first order problem is a linear function of az and y Use the substitution sin(a+) We obtain the following separable equation in the varables z and t 1-sin and use cos...
need help for this question in full answer 2. The deflection along a uniform beam with fexual Yigidity BI- and applied load f (x) = cos (-) satisfies the equation (a) Evaluate the deflection y (x)...

need help for this question in full answer 2. The deflection along a uniform beam with fexual Yigidity BI- and applied load f (x) = cos (-) satisfies the equation (a) Evaluate the deflection y (x). Hint: /cos(az)dz-asin (as)+C, /sin(as)dz=-a cos(az) +C (b) Find the influence function (Green's function) G (z,f), where 0 < ξ < 2, for this problem. Hint: Since 0 < ξ < 2, H(0-E)=0, H(2-E)=1. (c) Hence write the deflection of this beam as a definite...
We observe two point charges in the yz-plane: one of them has charge 2q and is located in (x,y,z)-(0,0,a) and the other...

We observe two point charges in the yz-plane: one of them has charge 2q and is located in (x,y,z)-(0,0,a) and the other has a charge of -3q and is located in (x,y,z)-(0,b,a) a) Calculate the dipole moment p, and p, for the two charges around (0,0,0), and sketch for a-2, b-3, c -1, the vector for the total dipole moment p for the configuration In addition to the two point charges, we now have an infinite grounded conductor placed in...

3. Suppose f(x,y,2)-sin2(x)-2sin(x) + y. 4 y z + 52.62. Find the minimum value of this function. you must find the point at which the minimum occurs and "prove" that the function really h...

3. Suppose f(x,y,2)-sin2(x)-2sin(x) + y. 4 y z + 52.62. Find the minimum value of this function. you must find the point at which the minimum occurs and "prove" that the function really has a mini mum there. Does the function have a maximum? If we restrict the variables to the ball of radius 1, centered at the origin, does the function have a maximum on that set? (You don't have to try to find the maximum but you should...
3. Suppose f(x,y,z) - sin2(x) - 2 sin(x)+y'-4yz+52-6z. Find the minimum value of this function- you must find the point at which the minimum occurs and "prove" that the function really ha...

3. Suppose f(x,y,z) - sin2(x) - 2 sin(x)+y'-4yz+52-6z. Find the minimum value of this function- you must find the point at which the minimum occurs and "prove" that the function really has a mini- mum there. Does the function have a maximum? If we restrict the variables to the ball of radius 1, centered at the origin, does the function have a maximum on that set? (You don't have to try to find the maximum but you should try to...

Observe that the point (1,1,1) satisfies the equation 2. Although we may not be able to write down a formula for z in terms of x and y there is a function z(x,y) that has continuous partial derivativ...

Homework Answers