Question

0.150 g benzophenone
0.100 g NaBH4

eagaph Show the theoretical result of the reactants and the product + Na,BO (CHszCHOH 1) For A al Calculate the formule molecular b) Molar mass i/mel ci Amount a Moles e) m 21 Fors a) Calculate the formuke mokcular bl Molar mass (mo c) Amount d] Moles 4) Calculate the formuk mobcua B) Molar mass (gimol co Amoune ig DI Moles El m A) Calculate the formde motecula B) Molar mass ie/mal Q Amount i i Mole Paragraph Show the theoretical result of the reactants and the product: OH NaBH4, B (CH32CHOH + Na3BO3 1) For A a) Calculate the formule molecular b) Molar mass (g/mol) c) Amount (g) d) Moles e) ml 2) For B a) Calculate the formule molecular b) Molar mass (g/mol) c) Amount (g) d) Moles e) mL 3) For C A) Calculate the formule molecular B) Molar mass (g/mol) C) Amount (g) D) Moles E) mL For D A) Calculate the formule molecular B) Molar mass (g/mol) C) Amount (g) D) Moles E) ml 4) 囝

Answer 1

Hope you like my powerpoint work.

NaBH, B (CH32CHOH + Na3BO3 Assuming 100 % conversion, 1 mole A will produce 1 mole of C but 1 mole of NaBH4 (B) will produce 1/3 amount of D. Na3BO3 128 Formula Molar mass (gm/mol) Amount (gm)0.150 C13H10 NaBH4 182 C13H120 184 38 0.152 (calculated from no of moles* molar mass 0.1123(calculated from no of moles*molar mass) 0.000877 0.100 Moles (amount/mole cular weight) mL (amount/densi 0.136 mL ty) 0.000824 0.002632 0.000824 0.150/1.1 Solid Not applicable as density of C is not known Solid