The Census Bureau groups data on households into census tracts, where each census tract has a total population of about 4,000 residents. Census tracts should be divided so that the households in the census tracts share certain characteristics, such as economic status. Even though most tracts are around 4,000 residents, there is some variability, which is the focus of this lab. In practice, census tracts usually have a population between 1,200 and 8,000 people.
I just need help with the table. I can probably figure it out if you just write out an explanation for how to do the first one or two samples.
Sample | Interval |
sample 1 |
M = 4226.09 You can be 95% confident that the population mean (μ) falls between 2997.7306 and 5454.4494. |
Likewise remaining samples will be calculate.
The Census Bureau groups data on households into census tracts, where each census tract has a total population of about 4,000 residents. Census tracts should be divided so that the households in the c...
Construct the confidence interval for the population mean μ c: 0.95, x-16.8, σ: 9.0, and n-100 A 95% confidence interval for μ is OD (Round to one decimal place as needed.) 6.1.27 Use the confidence interval to find the margin of error and the sample mean (1.58,2.06) The margin of error is (Round to two decimal places as needed) 6.1.31 Find the minimum sample size n needed to estimate μ for the given values of c, o, and E. cz...
1) A population of values has a distribution with μ=6μ=6 and σ=23.1σ=23.1. You intend to draw a random sample of size n=90n=90. According to the Central Limit Theorem: (a) What is the mean of the distribution of sample means? μ¯x=μx¯= (b) What is the standard deviation of the distribution of sample means? (Report answer accurate to 2 decimal places.) σ¯x=σx¯= (c) In a random sample of n=90, what is the probability that its sample mean is more than 4.2? Round...
1. A random sample of n measurements was selected from a population with standard deviation σ=13.6 and unknown mean μ. Calculate a 90 % confidence interval for μ for each of the following situations: (a) n=45, x¯¯¯=89.8 ≤μ≤ (b) n=70, x¯¯¯=89.8 ≤μ≤ (c) n=100, x¯¯¯=89.8 ≤μ≤ (d) In general, we can say that for the same confidence level, increasing the sample size the margin of error (width) of the confidence interval. (Enter: ''DECREASES'', ''DOES NOT CHANGE'' or ''INCREASES'', without the...
Over the past several months, an adult patient has been treated for tetany (severe muscle spasms). This condition is associated with an average total calcium level below 6 mg/dl. Recently, the patient's total calcium tests gave the following readings (in mg/dl). Assume that the population of x values has an approximately normal distribution. 9.9 8.8 10.9 9.3 9.4 9.8 10.0 9.9 11.2 12.1 (a) Use a calculator with mean and sample standard deviation keys to find the sample mean reading...