Question

i need help conducting the following two-way ANOVAS by hand. thanks in advance! also, i need help writjng up thr results in APA format.

avatlabic to yo A researcher is looking into the difference's dosage and gender for a drug that helps children focus. The researcher runs a 3x2 ANOVA with a sample size of 60 people and 1. gets the following results: a. SSotal 206.4 b. SSbetween -98.6 c. SSdosage- 10.7 d. SSpender = 40.6 100mg 50mg placebo totals IM-50, IM-47, |M-45, IM-50, Men SD- 1.35 SD 1.47 SD 1.46 SD-1.42 |M-65, SD = 1.54 |M-50, | SD-1.47 INT-55, | SD = 1.54 Women N-55, | SD = 1.67 IM-55, |M-51, M-47, totals SD- 1.47 SD 1.54 SD 1.49 A research is interested in the differences in motivation between those who are highly fused and not highly fused with with a goal and how reward plays a role in this relationship. The researcher runs a 2x2 ANOVA with a sample size of 75 people and gets the following results: 2. a. SStotal 305.6 b. SSbetween 200.5 c. SSfusion =128.6 d. SSreward 40.2 totals Rewarded Not Rewarded M-60, M 80, M 70, SD 6.7 SD- 3.50 SD-4.9 High fusion Low fusion | M-45, N-40, M-35, SD-8.5 SD 3.67 SD- 4.6 M-53, M-55, SD 7.6 SD 3.4 totals Name: 3. A researcher is looking into the difference's in response time between high and low SES individuals in both an experimental and control condition. The researcher runs a 2x2 ANOVA with a sample size of 100 people and gets the following results: a. SSootal 426.4 b. SSbetween = 121.8 c. SScondition 30.5 d. SSses 24.6 Experimental Control totals High SES | M = .4, SD =.2 | M = .6, | M1-5, SD1SD .15 Low SES | M = .6, SD = .l 5 | M = .8, I M = .7, SD 3SD-24 totals M .5, SD-.17 M-7, SD 2

Answer 1

1)

ANOVA
Source of Variation	SS	df	MS	F	P-value	F crit
Gender	40.6	1	40.6	19.584	4.95262E-05	4.026631
Dosage	10.7	3	3.566667	1.720	0.174184707	2.7826
Interaction	47.3	3	15.76667	7.605	0.000261662	2.7826
Error	107.8	52	2.073077
Total	206.4	59

SS interaction = SS between - SS gender - SS Dosage

SS Error = SS Total - SS between

MS = SS/df

F = MS /MS error

df A = a-1

df B = b-1

df interaction = (a-1)(b-1)

Formulas

ANOVA
Source of Variation	SS	df	MS	F	P-value	F crit
Gender	40.6	1	=B3/C3	=D3/D$6	=F.DIST.RT(E3,C3,52)	=F.INV.RT(0.05,C3,52)
Dosage	10.7	3	=B4/C4	=D4/D$6	=F.DIST.RT(E4,C4,52)	=F.INV.RT(0.05,C4,52)
Interaction	=98.6- (B3+B4)	3	=B5/C5	=D5/D$6	=F.DIST.RT(E5,C5,52)	=F.INV.RT(0.05,C5,52)
Error	=206.4-98.6	=C7-SUM(C3:C5)	=B6/C6
Total	=SUM(B3:B6)	59

Here Gender and Interaction are significant as their p-values are less than 0.05
Dosage is not significant at alpha = 0.05