(a) From small angle approximation, we have
y = mL / d
The path difference is given as
x = / 2
so,
= 2dy / L
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(b) Putting in the given values
= 2 * 15e-6 * 2.7e-3 / 590e-9 * 1.9
= 0.227 radians
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(c) I am not sure about this part, but I do know that for 2 slits, the intensity Io and I are related as
I = 4Iocos2 ( / 2)
so, from here we can solve for Io
I am getting it as
Io = 21.53 W/m2
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