here,
m1 = 4 kg
m2 = 6 kg
the mass of pulley , M = 8 kg
the acceleration of 4 kg mass , a = net force /effective mass
a = ( m2 - m1) * g /(m1 + m2 + 0.5 * M * r2^2 /r2^2)
a = ( 6 - 4) * 9.81 /( 6 + 4 + 0.5 * 8 )
a = 1.4 m/s^2
the acceleration of 4 kg mass is 1.4 m/s^2 upwards
1. The picture below shows a double pulley system where the 4kg mass is wound on the bigger groove(r2) and the 6kg mass is wound on the smaller groove(ri) with half the radius as the bigger one(r...
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Two metal disks, one with radius R1 = 2.50 cm and mass M1 = 0.800 kg and the other with radius R2 = 5.10 cm and mass M2 = 1.70 kg, are welded together and mounted on a frictionless axis through their common center (Figure 1). Part A What is the total moment of inertia of the two disks? Part B A light string is wrapped around the edge of the smaller disk, and a 1.50 kg block is suspended from the free end...
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