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1. The picture below shows a double pulley system where the 4kg mass is wound on the bigger groove(r2) and the 6kg mass is wo
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Answer #1

here,

m1 = 4 kg

m2 = 6 kg

the mass of pulley , M = 8 kg

the acceleration of 4 kg mass , a = net force /effective mass

a = ( m2 - m1) * g /(m1 + m2 + 0.5 * M * r2^2 /r2^2)

a = ( 6 - 4) * 9.81 /( 6 + 4 + 0.5 * 8 )

a = 1.4 m/s^2

the acceleration of 4 kg mass is 1.4 m/s^2 upwards

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1. The picture below shows a double pulley system where the 4kg mass is wound on the bigger groove(r2) and the 6kg mass is wound on the smaller groove(ri) with half the radius as the bigger one(r...
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