What is the energy released in this β−β−nuclear reaction 239 93Np→239 94Pu+0−1e932 39Np→942 39Pu+−10e? (The atomic mass of 239Np239Np is 239.052939 u and that of 239Pu239Pu is 239.052163 u)
What is the energy released in this β−β−nuclear reaction 239 93Np→239 94Pu+0−1e932 39Np→942 39Pu+−10e? (The atomic mass of 239Np239Np is 239.052939 u and that of 239Pu239Pu is 239.052163 u) 6. What i...
What is the energy released in this β+β+ nuclear reaction 2815P→2814Si+01e1528P→1428Si+10e? (The atomic mass of 28P28P is 27.992315 u and that of 28Si28Si is 27.976926 u) MeV
What is the energy released in this nuclear reaction 1223Mg → 1323Al + -10e? (The atomic mass of 23Mg is 22.994123 u and that of 23Al is 22.989769 u). I got 3.54475 MeV but it is incorrect, pelase help and include steps, I really need to understand this problem!
6. What is the energy released in this ß nuclear reaction 140.910962 u) Ba → La + le? (The atomic mass of 141 Ba is 140.914411 u and that of MLa is 57 MeV 6. What is the energy released in this ß nuclear reaction 140.910962 u) Ba → La + le? (The atomic mass of 141 Ba is 140.914411 u and that of MLa is 57 MeV
8, what is the energy released in this 3" nuclear reaction u) e? (The atomic mass of 22Na is 21.994436 u and that of 22 Ne is 21.991385 Na → Ne + x 2.3315445 Mev
What is the energy released in this β+ nuclear reaction 23/12Mg→23/11Na+0/1e (The atomic mass of 23Mg is 22.994123 u and that of 23Na is 22.989769 u)
. What is the energy released in this β + nuclear reaction 28 15 P → 28 14 S i + 0 1 e ? (The atomic mass of 28 P is 27.992315 u and that of 28 S i is 27.976926 u)
In nuclear reactors an example reaction would be Np-239 (nuclear mass defect = 49.3110MeV/c^2) to Pu-239 (nuclear mass defect = 48.5882MeV/c^2) + other products. Calculate the magnitude of the difference in total nuclear binding energy before and after. (Answer in MeV with three sig figs)
What is the energy released in this β − nuclear reaction 40 19 K → 40 20 C a + 0 − 1 e ? (The atomic mass of 40 K is 39.963998 u and that of 40 C a is 39.962591 u)
What is the energy released in this β + nuclear reaction 44 23 V → 44 22 T i + 0 1 e ? (The atomic mass of 44 V is 43.974111 u and that of 44 T i is 43.95969 u)
In nuclear reactors an example reaction would be Np-239 (nuclear mass defect = 49.3110 MeV/c^2) to Pu-239 (nuclear mass defect = 48.5882 MeV/c^2) + other products. For a mole of these reactions calculate the magnitude in the change in energy. (Answer in GJ with three sig figs)