We can use parametric test (ANOVA) where our Null Hypothesis: there is no difference between the means
Alternate Hypothesis: at least one pair of mean is different
When we compute we get the following results:
Source of Variation | SS | df | MS | F | P-value |
Between Groups | 1952.644 | 2 | 976.3219 | 93.5756 | 2.52E-14 |
Within Groups | 344.3058 | 33 | 10.43351 | ||
Total | 2296.95 | 35 |
So the p-value is `~ 0
thus we reject the null hypothesis and say there is at least one pair of mean which is different
Also computed Kruskal-Wallis Test, which is a non parametric one with the same hypothesis above,
Since it is observed that = 23.568 > = 5.991, it is then concluded that the null hypothesis is rejected.
Using the P-value approach: The p-value is p ~ 0, and since p <0.05, it is concluded that the null hypothesis is rejected.
Now we compute t-statistics for all pairs:
P value | ||
DC & MK | 3.82E-10 | Different |
DC & ( DC + MK) | 5.7E-10 | Different |
(DC + MK) & DC | 0.41915 | Same |
So only the (DC + MK ) and DC has same effect and the rest two are different
II. An experiment to ascertain the effect of chocolate on cardiovascular health was performed using three different "types" of chocolate: (1) 100 gm. Dark Chocolate (DC); (2) 100 gm. Dark...
PLEASE SHOW YOUR WORK STEP BY STEP An article in Nature describes an experiment to investigate the effect on consuming chocolate on cardiovascular health ("Plasma Antioxidants from Chocolate," 2003, Vol. 424, pp. 1013). The experiment consisted of using three different types of chocolates: 100 g of dark chocolate, 100 g of dark chocolate with 200 ml of full-fat milk, and 200 g of milk chocolate. Twelve subjects were used, seven women and five men with an average age range of...