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II. An experiment to ascertain the effect of chocolate on cardiovascular health was performed using three different types o
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Answer #1

We can use parametric test (ANOVA) where our Null Hypothesis: there is no difference between the means

Alternate Hypothesis: at least one pair of mean is different

When we compute we get the following results:

Source of Variation SS df MS F P-value
Between Groups 1952.644 2 976.3219 93.5756 2.52E-14
Within Groups 344.3058 33 10.43351
Total 2296.95 35

  So the p-value is `~ 0

thus we reject the null hypothesis and say there is at least one pair of mean which is different

Also computed Kruskal-Wallis Test, which is a non parametric one with the same hypothesis above,

Since it is observed that \chi ^{2} = 23.568 > \chi ^{2} = 5.991, it is then concluded that the null hypothesis is rejected.

Using the P-value approach: The p-value is p ~ 0, and since p <0.05, it is concluded that the null hypothesis is rejected.

Now we compute t-statistics for all pairs:

P value
DC & MK 3.82E-10 Different
DC & ( DC + MK) 5.7E-10 Different
(DC + MK) & DC 0.41915 Same

So only the (DC + MK ) and DC has same effect and the rest two are different

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II. An experiment to ascertain the effect of chocolate on cardiovascular health was performed using three different "types" of chocolate: (1) 100 gm. Dark Chocolate (DC); (2) 100 gm. Dark...
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