Question

can someone show me the steps for this

following corridor have fallen out of nd your investigation has 13. A fter a recent power outage, the traffic signals along the coordination. Int therection 2is the main (master) intersection a should the offset be (3%) ? r h s one way (from intersection 1 to 3),sketch the existing bandwidth for th ofi lcated on your new phasing (no need to measure, just suegested that the offset for intersection 3 needs to be adjurt a. If the speed along this corridor is 34 mph, how many seco b. Assuming traffic the corridor (5%). [COOf Redraw the phasing at intersection 3 with the following l. Show where the offset is show where those sec Be sure to Show the new bandwidth (3%). 20 Sccends onds would start and end) (3%). defire the green and red intervals in your updated phasing (Z%). iii. 3 1,000 2 ,000 Red Green nelle ellow Time (s)

Answer 1

(a) Given speed at the corridor as 34 mph. And the distance between the two signals is 1000' or 1000 ft.

Now, 34 mph = 49.9 fps or 50 fps.

Offset = ( 1000 ft ) / ( 50 fps ) = 20 seconds.

(b) Bandwidth is that band of vehicles who meet green at the first signal and keep meeting until the last one of the coordinated signals, in this case it being the third one. So draw a line, from first signal, from the point where the green signal is beginning. And attach to the next same point of signal and continue the line. Do it same from ending point of green signal and continue parallelly to the first. The region within the two lines will be the bandwidth, as you've shared in the photo.

(i) Showing offset - as middle one is the master signal, the difference in point of starting green cycle of master signal and the two other signals is what is the offset. As shown in the bottom part of the image, gap of two green cycles starting is offset.

(ii) Redraw the third signal, with green cycle starting with the offset. Then just copy the cycle lengths of red and yellow, then again the next cycle. With this drawn again, draw the new bandwidth, as we did in part (a).