Question

Review Part A The tune-up specifications of a car call for the spark plugs to be tightened to a torque of 41.0 Nm. You plan to tighten the plugs by pulling on the end of a 27.0-cm-long wrench. Because of the cramped space under the hood, you'll need to pull at an angle of 105 with respect to the wrench shaft. With what force must you pull? Submit Request Answer Provide Feedback

Answer 1

The anale Foathe moment given thot 41 length23 I.S oSto the 。Shoftis 30 to the I.SI 0:866 = 1.74V

Answer 2

Context Explaination

Dig if you will the picture.

The purple represents the wrench.

The RED represents our mystery.

The blue is the angle of the applied force.

The force is being applied at a 130° angle.

The force perpendicular will be perpendicular to the wrench. So where that applied force crosses the wrench in a clockwise motion, creates a 50° angle.

That 130° angle and the 50° angle add up to 180°, which is interesting but I don't know enough to explain it.

The perpendicular force then is the sin(50°).

Application

The math I had for this problem was 38N*m was our torque while the length of the wrench is 21cm. The force was applied at 130°, what was the force of the pull?

We know that Torque = (radius)(force)(direction(?))

If we solve that algebraically, we would divide (radius) and (direction(?)) away from the force. That will be rewritten as...

Force = (torque) / (radius)(direction(?))

Then we'd plugin.

Force = (38N*m) / (0.21m)(sin(50)) ≈ 236N (Rounded)