2) A 460 V, 4-pole, 60 Hz, Y-connected, 40 hp, design class A induction motor is tested with the following results: No-load: 460 V, 8.7 A, 2500 W. 60 Hz Locked rotor: 42 V.48 A, 31 10 W. 12 Hz DC tes...
:00 Hz, six-pole Y-connected 40-hp design class B induction motorX -0.4Xux, and 3. A 460-V. 60Hz, six-pole Y-connected 40-hp X2-0.6XLR) is tested in the laboratory, with the following results: No load Test: 460 V, 32.7 A, 4,664 W, 60 Hz Locked Rotor(LR) Test: 36.2 V, 58.0 A, 2,573 W, 15 Hz: DC test: 12.0 V, 59.0 A: Find the equivalent circuit parameters Ri(10pts),R (10pts),X (15pts),X:(15pts), and Xx(10pts) of this motor as shown in Fig. 3. (60pts) Fig. 3
. A 460-V 460-V, 25-hp, 60-Hz, six-pole, Y-connected induction motor has the following impedanc ohms per phase referred to the stator circuit. Ri= 0.212 R2 = 0.282 X1 = 1.055 12 X2 = 1.055 22 XM = 33.9 W The total rotational losses are 1100 W and are assumed to be constant. The core loss is lumped with the rotational losses. For a rotor slip of 4% at the rated voltage and rated frequency, a) The input power b) Peony...
A 208-V, six-pole, Y-connected, 25-hp design class B induction motor is tested in the laboratory, with the following results: No load: 208 V, 24.0 A, 1400 W, 60 Hz Locked rotor: 24.6 V, 64.5 A. 2200 W, 15 Hz 13.5 V, 64 A de test: a) Find the parameters of the induction motor equivalent circuit. b) Calculate the stator current if the slip is 0.02.
III A 208-V, 60 Hz, six-pole Y-connected 25-hp design class B induction motor is tested in the laboratory, with the following results: No load test: Blocked-rotor test: DC test: 208 V, 22.0 A, 1200 W, 60 Hz 24.6 V, 64.5 A, 2200 W, 15 Hz 13.5 V, 64 A a) Find the equivalent cireuit of this motor. (4 marksy)
Name: Student ID: A 208-V, six-pole, Y-connected, 25-hp design class B induction motor is tested in the laboratory, with the following results: No load: 208 V, 24.0 A, 1400 W, 60 Hz Locked rotor: 24.6 V, 64.5 A, 2200 W, 15 Hz dc test: 13.5 V, 64 A a) Find the parameters of the induction motor equivalent circuit. b) Calculate the stator current if the slip is 0.02.
please show psuedocode 4) A 208V, 60 Hz, 6 pole, Y-connected, 25 hp induction motor is tested in the laboratory with the following results: No Load: 208 V,22 A, 1200 W,60 Hz Locked Rotor: 24.6 V,64.5 4,2200 W.15 Hz DC Test: 13.5 V.64 4 a) Find the equivalent circuit parameters of this motor, draw the circuit and write the values beside each component. (10) b) Using MATLAB, write a program to plot its torque-speed characteristics curve. (10) 4) A 208V,...
Example 20-4. A 200 hp (150 kW), 460 V, 3-phase, 3520 r/min, 60 Hz induction motor has a locked-rotor torque of 600 Nom and a locked-rotor current of 1400 A (same motor as in Example 20- 2). Two autotransformers, connected in open delta, and having a 65 percent tap, are employed to provide reduced-voltage starting. Calculate a. The apparent power absorbed by the motor b. The apparent power supplied by the 460 V line c. The current supplied by the...
fundamentals of machines Problem A 460-V, four-pole, 60-Hz, Y-connected induction motor has the following equivalent circuit components Ri-0.15Ω R,-0.154 Ω X-1.066 Ω Xi,-20 Ω Xi-0.852 Ω Pmech 400 w Pmisc 150 Pcore 400 w Write MATLAB script to plot on two separate figures: a) the torque versus speed of the motor. b) the converted power versus speed of the motor. Problem A 460-V, four-pole, 60-Hz, Y-connected induction motor has the following equivalent circuit components Ri-0.15Ω R,-0.154 Ω X-1.066 Ω Xi,-20...
A 4 phase, 460 V, 60 Hz, 26.8 hp, 4 pole, Y-connected induction motor draws 25 A at a power factor of 0.9 lagging. Core loss is 900 W, stator copper loss is 1100W, friction and winding losses are 300 W, and stray loss is neglected. The machine shaft rotates at 1738 rpm. Calculate the air gap power and output load torque - [Induction Motor - 15 points) A three-phase, 460 V, 60 Hz, 26.8 hp, 4-pole, Y-connected induction motor...
A 3-phase, 208 V, 60 Hz, 30 hp, four-pole induction motor has the following equivalent circuit parameters. R1 = 0.2 Ω, , , Xm = 12Ω.The rotational loss is 500 W. For a slip of 5%, calculate (a) The motor speed in rpm and radians per sec (b) The current drawn by the motor from the power supply (c) The stator cu-loss (d) The air gap power (e) The rotor cu-loss (f) The shaft power (g)The developed torque and the shaft torque (h) The efficiency of the motor Use...