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EXIT 211 A A 2,125 ft equal tangent vertical curve joins a +2.2% grade to-3.6% grade. The PVI of the vertical curve is statio
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Answer #1

Ans a) Station at overhead sign = 55 + 85 ft

Height of bottom of sign from road =18 ft

Elevation of bottom of sign = (55+85) + (0+18)

= 55 +103

Also, we know,

PVI - PVC = L/2

PVC = PVI - L/2

= (55+21) - (2125/2)

= 44 + 58.5

PVT - PVI = L/2

PVT = L/2 + PVI

= (2125/2) + (55+21)

= 65 + 83.5

Now, PVI elevation = PVC elevation + (0.022 x 2125/2)

150 = PVC elevation + 23.375

PVC elevation = 126.625 ft

PVT elevation = PVI elevation + (0.022 x 2125/2)

PVT elevation = 150 + 23.375

= 173.35 ft

Ans b) Y = A (L/2)2 / 200 L

A = change in grade = 5.8

L = 2125 ft

Y = 15.40 ft

Offset required is 15.4 ft < 18ft , so SSD is not a concern

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EXIT 211 A A 2,125 ft equal tangent vertical curve joins a +2.2% grade to-3.6% grade. The PVI of the vertical curve is station 55+21 at elevation 150 ft. To meet MUTCD standards for advance guida...
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