a) critical points are:
(0,1), (0,-1), (2,1), (2,-1), (-2,1), (-2,-1)
jacobian matrix is
and its eigenvalue is
so at (0,1) Eigenvalues of the Jacobian matrix is +10,-10, so we get a saddle point, which is an unstable equilibrium point.
at (0,-1) Eigenvalues of the Jacobian matrix is +10i,-10i, so we get critical point that is spiral source, and therefore an unstable equilibrium point.
at (2,1) Eigenvalues of the Jacobian matrix is +14i,-14i, so we get critical point that is spiral source, and therefore an unstable equilibrium point.
at (2,-1) Eigenvalues of the Jacobian matrix is +14,-14, so we get a saddle point, which is an unstable equilibrium point.
at (-2,1) Eigenvalues of the Jacobian matrix is +14i,-14i, so we get critical point that is spiral source, and therefore an unstable equilibrium point.
at (-2,-1) Eigenvalues of the Jacobian matrix is +14,-14, so we get a saddle point, which is an unstable equilibrium point.
b)
Where, E = total energy
H(x, y)=E=
PLEASE HELP !!!! thanks 14. 12 points! The phase portrait (without arrows) of a non-linear syster dz 3-32, 16r dt 2 dy dt a) Mark all critical points directly on the 2 diagram, and classify them...