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16. If 1050 g of aluminum metal with a specific heat capacity of 0.902 g C at-20°C is placed in liquid water at 0.00 °C, how many grams of liquid water are frozen by the time that the aluminum metal...
4. What is the average specific heat capacity of the unknown metal in this experiment? 5....
4. What is the average specific heat capacity of the unknown metal in this experiment? 5. What is the unknown metal? Use Table 1 for reference. Table 2: Mass Mass (8) Water 49.2g Unknown Metal Strip 22.3g Table 3: Specific Heat Data Temperature (°C) Trial 1 Trial 2 Time (minutes) Trial 3 Initial 23 22.6 23.2 5 minutes 23.6 23.3 24.3 6 minutes 23.6 23.3 24.3 7 minutes 23.66 23.3 24.2 8 minutes 23.6 23.3 24.2 9 minutes 23.4 23.3...
A 95.0g piece of metal (with a specific heat of 1.55 J/g°C) is heated to 375°C...
A 95.0g piece of metal (with a specific heat of 1.55 J/g°C) is
heated to 375°C and then placed into a calorimeter, which contains
60.0g of ice in equilibrium with 40.0g of liquid water. How many
grams of ice will melt in this process? A) 7.3, B) 16.6, C) 34.2,
D) 22.9, or E) 52.4. [The key says the answer is B]. Please show all work. Thank
you!
9. A 95.0 g piece of metal (with a specific heat of...
You add 100.0 g of water at 51.0 °C to 100.0 g of ice at 0.00...
You add 100.0 g of water at 51.0 °C to 100.0 g of ice at 0.00 °C. Some of the ice melts and cools the water to 0.00 °C. When the ice and water mixture reaches thermal equilibrium at 0 °C, how much ice has melted? (The specific heat capacity of liquid water is 4.184 J/g · K. The enthalpy of fusion of ice at 0 °C is 333 J/g.) Mass of ice = References Use the References to access...
How many grams of ice at -15°C must be added to 705 grams of water that...
How many grams of ice at -15°C must be added to 705 grams of water that is initially at a temperature of 88°C to produce water at a final temperature of 11°C. Assume that no heat is lost to the surroundings and that the container has negligible mass. The specific heat of liquid water is 4190 J/kg·C° and of ice is 2050 J/kg·C°. For water the normal melting point is 0.00°C and the heat of fusion is 334 × 103...
Specific Heat Capacity A 21.5-g sample of an unknown metal is heated to 94.0°C and is...
Specific Heat Capacity A 21.5-g sample of an unknown metal is heated to 94.0°C and is placed in a insulated container containing 128 g of water at a temperature of 21.4°C. After the metal cools, the final temperature of the metal and water is 25.0°C. Calculate the specific heat capacity of the metal, assuming that no heat escapes to the surroundings. Heat loss=Heat gained. Specific Heat Capacity of water is 4.18 J/g/K in this temperature range. Submit Answer Incompatible units....
A 3.00-g sample of aluminum pellets (specific heat capacity = 0.89 J/°C·g) and a 11.00-g sample...
A 3.00-g sample of aluminum pellets (specific heat capacity = 0.89 J/°C·g) and a 11.00-g sample of iron pellets (specific heat capacity = 0.45 J/°C·g) are heated to 100.0 °C. The mixture of hot iron and aluminum is then dropped into 73.8 g water at 22.0 °C. Calculate the final temperature of the metal and water mixture, assuming no heat loss to the surroundings. Please be super specific on how you get to each step!
A 3.00-g sample of aluminum pellets (specific heat capacity=0.89 J/°C g) and a 18.50-g sample of...
A 3.00-g sample of aluminum pellets (specific heat capacity=0.89 J/°C g) and a 18.50-g sample of iron pellets (specific heat capacity = 0.45 J/°C-g) are heated to 100.0 °C. The mixture of hot iron and aluminum is then dropped into 77.4 g water at 22.0 °C. Calculate the final temperature of the metal and water mixture, assuming no heat loss to the surroundings. Final temperature = 20.23 °C An error has been detected in your answer. Check for typos. miscalculations...
3. A 2.00 g block of a metal (specific heat = 2.09 J g: Kl) at 80.0 °C is placed into container with 10.0 g liquid wate...
3. A 2.00 g block of a metal (specific heat = 2.09 J g: Kl) at 80.0 °C is placed into container with 10.0 g liquid water (specific heat = 4.18 Jg' K ) at 10.0°C. What is total AS in JK?
20. How many grams of water can be cooled from 35 to 20 °C by evaporation of 60 grams of water? (heat of vaporizati...
20. How many grams of water can be cooled from 35 to 20 °C by evaporation of 60 grams of water? (heat of vaporization of water = 2.4 kJ/g) (specific heat of water = 4.18J/mole K) A) 1.6 x 10 g B) 2.3 x 103g C) 2.6 g D) 1.6 g E) 2.3 g
The specific heat of aluminum is 0.900 J/g*C. How many joules of heat are absorbed by...
The specific heat of aluminum is 0.900 J/g*C. How many joules of heat are absorbed by 15.0 grams of AI if it is heated from 20.0 C to 60.0 C. Please show how to work out.
4. What is the average specific heat capacity of the unknown metal in this experiment? 5. What is the unknown metal? Use Table 1 for reference. Table 2: Mass Mass (8) Water 49.2g Unknown Metal Strip 22.3g Table 3: Specific Heat Data Temperature (°C) Trial 1 Trial 2 Time (minutes) Trial 3 Initial 23 22.6 23.2 5 minutes 23.6 23.3 24.3 6 minutes 23.6 23.3 24.3 7 minutes 23.66 23.3 24.2 8 minutes 23.6 23.3 24.2 9 minutes 23.4 23.3...
A 95.0g piece of metal (with a specific heat of 1.55 J/g°C) is
heated to 375°C and then placed into a calorimeter, which contains
60.0g of ice in equilibrium with 40.0g of liquid water. How many
grams of ice will melt in this process? A) 7.3, B) 16.6, C) 34.2,
D) 22.9, or E) 52.4. [The key says the answer is B]. Please show all work. Thank
you!
9. A 95.0 g piece of metal (with a specific heat of...
You add 100.0 g of water at 51.0 °C to 100.0 g of ice at 0.00 °C. Some of the ice melts and cools the water to 0.00 °C. When the ice and water mixture reaches thermal equilibrium at 0 °C, how much ice has melted? (The specific heat capacity of liquid water is 4.184 J/g · K. The enthalpy of fusion of ice at 0 °C is 333 J/g.) Mass of ice = References Use the References to access...
Specific Heat Capacity A 21.5-g sample of an unknown metal is heated to 94.0°C and is placed in a insulated container containing 128 g of water at a temperature of 21.4°C. After the metal cools, the final temperature of the metal and water is 25.0°C. Calculate the specific heat capacity of the metal, assuming that no heat escapes to the surroundings. Heat loss=Heat gained. Specific Heat Capacity of water is 4.18 J/g/K in this temperature range. Submit Answer Incompatible units....
A 3.00-g sample of aluminum pellets (specific heat capacity=0.89 J/°C g) and a 18.50-g sample of iron pellets (specific heat capacity = 0.45 J/°C-g) are heated to 100.0 °C. The mixture of hot iron and aluminum is then dropped into 77.4 g water at 22.0 °C. Calculate the final temperature of the metal and water mixture, assuming no heat loss to the surroundings. Final temperature = 20.23 °C An error has been detected in your answer. Check for typos. miscalculations...
3. A 2.00 g block of a metal (specific heat = 2.09 J g: Kl) at 80.0 °C is placed into container with 10.0 g liquid water (specific heat = 4.18 Jg' K ) at 10.0°C. What is total AS in JK?
20. How many grams of water can be cooled from 35 to 20 °C by evaporation of 60 grams of water? (heat of vaporization of water = 2.4 kJ/g) (specific heat of water = 4.18J/mole K) A) 1.6 x 10 g B) 2.3 x 103g C) 2.6 g D) 1.6 g E) 2.3 g
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