I would solve 6th question
We would use the hypothesis test for proportion
Here value of proportion p=0.65
Let us first find the value of np=0.65(144)=93.6 and nq=144(0.35)=50.4 which are both greater than 5
So We would use Z test
The claim is that at least 65% of students plan to going to college
Null hypothesis:Ho:p=0.61
Alternate hypothesis:p>0.61
Because it is one tailed t test
and level o f significance =0.05
So critical value will be 1.645
Here sample proportion will be given as
So standardized test statstic is
absolute value of Z stat is greater than Z critical
Z stat>Z critical
we would reject null hypothesis
so our claim is true that at least 65% of students are planning to going to college
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