Design is very simple. Since input x is in binary, so if the rightmost bit is 1, then simply we have to replace rightmost 1 by 0 and we are done. If the rightmost bit is 0 then we have to replace 0 by 1 and keep on moving left and replace 0 by 1, and when 1 is encountered then replace that 1 by 0 and we are done.
Once we are done, we simply have to move to rightmost input position with ending state being q1.
//Replace 1 by 0 and we are done
//Replace 0 by 1 and move left
//Simply go to right end
//simply move right
//Once input is end, move one position left and go to q1 and finished
Please comment for any clarification.
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