Patients coming to a medical clinic have a mean weight of 207.6 pounds, with a standard deviation of 22.6 pounds. The distribution of weights is not assumed to be symmetric. Between what two weights does Chebyshev's Theorem guarantees that we will find at least 95% of the patients? Round your answers to the nearest tenth.
Solution :
Given that,
mean = = 207.6
standard deviation = = 22.6
Using standard normal table,
P(Z > z) =95 %
1 - P(Z < z) = 0.95
P(Z < z) = 1 - 0.95
P(Z < -1.65) = 0.05
z = -1.65
Using z-score formula,
x = z * +
x = -1.65 * 22.6 + 207.6 = 170.3
The patients = 170.3
Patients coming to a medical clinic have a mean weight of 207.6 pounds, with a standard deviation of 22.6 pounds. The distribution of weights is not assumed to be symmetric. Between what two weights d...
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