please help with theses statistics problems. show all work and explain finals are this week 11) ln gemeral, if probability of s Type I error is lncreased, whut hagpens to the prohality of a Type...
11) ln gemeral, if probability of s Type I error is lncreased, whut hagpens to the prohality of a Type t1 eur B) increases Dj need more infoemation no chanpe 12) A u untyenity dean is inderested in determining the rroportion of stdents who receive some sort of financial aid. Racher than heraine e records for all students, the dean randomly selects 200 stadents and Eeds that 118 of them are receiving financial a fr p is (052, 066). İnterpret this interal. nterval foe A) we are 95% confident that 50% ofthe students are on somr sort criancial aid. B)Weare 95% confident that between 52% and 66%ofde sampled stadens reserve s me sort of nuncial aid. O q5% ofthe students get between 52% and 66% of their tuition paid for by fin ncial aid. Dw eare 95% confident that the true proportion of all students receiving financial aid is between 052 and 0.66. 13) What can be done to the sample size and confldence level to peovide a confidence interval? acrease the sample sine, decrease the confidensce level D) increase the sample size, increase the confidence level A) decrease the sample size, decrease the confidence level C) decrease the sample size, increase the cenidence level 14) A sample of 14 joint specimens of a particular type gave as stress of 8.50 MIPa and a sample for the true average proportional limit stress mean proportional mit s confidenc standard deviation of 80 MPa. of all such joints (previde to & decimal place) Calculate and interpret a瘚 our 8.50-13,012) : ls can beseeible to stress cornosion cracking under certain conditices. A materials enginer is intercsted in determining the proportion of steel alloy failures that are due to stress corrosion cracking data, how large a sample must be taken to be sure that a 99% confidence Intmal will have a margin of emor of no more than 0.05 b. Based on a previos study, approximately 15% of filures were caused by stress anrosion cracking. Based oa this data, how large a sample must be taken to be sure that a 99% oonfidence interval will have margin ofenor of no more than ads 85 n- a.48
11) ln gemeral, if probability of s Type I error is lncreased, whut hagpens to the prohality of a Type t1 eur B) increases Dj need more infoemation no chanpe 12) A u untyenity dean is inderested in determining the rroportion of stdents who receive some sort of financial aid. Racher than heraine e records for all students, the dean randomly selects 200 stadents and Eeds that 118 of them are receiving financial a fr p is (052, 066). İnterpret this interal. nterval foe A) we are 95% confident that 50% ofthe students are on somr sort criancial aid. B)Weare 95% confident that between 52% and 66%ofde sampled stadens reserve s me sort of nuncial aid. O q5% ofthe students get between 52% and 66% of their tuition paid for by fin ncial aid. Dw eare 95% confident that the true proportion of all students receiving financial aid is between 052 and 0.66. 13) What can be done to the sample size and confldence level to peovide a confidence interval? acrease the sample sine, decrease the confidensce level D) increase the sample size, increase the confidence level A) decrease the sample size, decrease the confidence level C) decrease the sample size, increase the cenidence level 14) A sample of 14 joint specimens of a particular type gave as stress of 8.50 MIPa and a sample for the true average proportional limit stress mean proportional mit s confidenc standard deviation of 80 MPa. of all such joints (previde to & decimal place) Calculate and interpret a瘚 our 8.50-13,012) : ls can beseeible to stress cornosion cracking under certain conditices. A materials enginer is intercsted in determining the proportion of steel alloy failures that are due to stress corrosion cracking data, how large a sample must be taken to be sure that a 99% confidence Intmal will have a margin of emor of no more than 0.05 b. Based on a previos study, approximately 15% of filures were caused by stress anrosion cracking. Based oa this data, how large a sample must be taken to be sure that a 99% oonfidence interval will have margin ofenor of no more than ads 85 n- a.48