Question

good day these are three separate questions that I would like help with. Thank you

The overall faction in the lead storage battery is 25℃ for this battery when IHM4 45 M. Calculate the lead storage battery. 7s. Consider the galvanic cell based on the following halr- reactions: a. Determine the overall cell reaction and calculale ll b. Calculate AGe and K for the cell reaction at 25°C e, Calculate鵀떼 at 25℃ Whe川Zn2+卜#: 0.10 Mand IFe1 10x 10 M K 10x 10'3 87. Cadmium sulfide is used in some semiconductor applications. Calculate the value of the solubility product constant (Kp) for g Cds given the following standard reduction potentials: CdS(s) + 2e → Cd(s) + S2 (aq) To -1.21 V CgPi (aq) + 2e → Cd(s) 88. For the following half-reaction seoz y

Answer 1

75)

a)

overall cell reaction

Zn(s) + Fe2+(aq) ------> Zn2+(aq) + Fe(s)

E0cell = E0(reduction ) - E0(oxidation)

= - 0.44 - ( - 0.76)

= -0.44 + 0.76

E0cell = 0.32 V

b)

$\Delta$G0 = - nFE0cell

n = 2 ( two electrons transfer )

$\Delta$G0 = - 2 * 96485 * 0.32

$\Delta$G0 = - 61750.4 J

$\Delta$Go = - RTlnK

- 61750.4 = - 8.314 * 298.15 * lnK

lnK = 61750.4 / ( 8.314 * 298.15 )

lnK = 61750.4 / 2478.82

lnK = 24.91

K = e^24.91

K = 6.6 * 10^10  

c)

Ecell = E0cell + (0.059 / n) * log(Fe2+ / Zn2+)

Ecell = 0.32 + (0.059 / 2) * log(1.0*10^-5  / 0.1 )

Ecell = 0.32 + ( 0.0295 * log ( 10^-6) )

Ecell = 0.32 + ( 0.0295 * -6 )

Ecell = 0.32 - 0.18

Ecell = 0.14 V