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(d) 7650 (e) None of the above Question 7 [18 Points]-Instruction Set Architecture (ISA) I. Suppose an instruction set has 32
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Answer #1

Every instruction has 8 bit opcode.

Instruction size is 32 bit.

Immediate operand is 12 bit.

Some instructions have three register operands.

Instruction size - (3×(register operand)+opcode)=immediate operand

=> 32-(3n+8)=12

=>3n+8=20

=>3n=12

=>n=4

Now, the number of registers that the instruction set support is,

2^n =2^4 = 16

Therefore the correct option is (c) 16.

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(d) 7650 (e) None of the above Question 7 [18 Points]-Instruction Set Architecture (ISA) I. Suppose an instruction set has 32-bit instructions. Every instruction has an 8-bit opcode and a 12- bit...
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