Question

Draw structure from IR, formula c3h6o2

Analyst Date Thursday, May 09, 2019 851 AM 70 1047 39 20m 95em-1 1744.59cm-1 1437 80cm-1 C-O COH 60- 3400 45cm-1 On 50 40- 30 201 10 500 1000 000 3500 3000002000 1500 cm-1 Sample 549 By Administrator Date Thursday, May 09 2019 Administrator 549,001 _ ー -.

Answer 1

H+X-N Given formulaisCH,02 DBE C+1 Here, Cisnumber of carbon atoms, Hisnumber of hydrogen atoms, Xisnumber of halogen atoms and Nisnumber of nitrgen atoms.DBEissum of double bonds andnumber of rings. Calculate DBEis as follows: DBE C+1- DBE-C+1- HX-N -3+1-6+0-0 -4-3 -1 Thus, unknown compound does have one double bondor aring Dueto presence of U shapedIR stretch at 3300cm suggests that there is a HOgroup. Dueto presence of 1744 cm there is acarbonyl group. Carboxylicacid shows at1710cm1 Hence,structure is

CH3 HO I-hydroxypropan-2-one