Question

Magneticd fields..

Im kinda lost in this sample problem im trying to study.. could someone pls clarify my questuon i wrote in green..

My question is why they used that formula or can u relate that to the formula i shown to u from my book. Whyvthey ignore that part pf the formula for this problem??

Also i dont understand the limit for 1/r could someone pls help explain..

Any helpful help would be appreciated..

a Cary Cos 2气 ps u xoluh 6-2 FARADAY'S LAW ELECTROM 239 W OF ELECTROMAGNETIC INDUCTION A MOVING CIRCUIT IN A TIME-VARYING MAGNETIC FIELD When a charge q moves with a velocity u in a region where both an electric field E and a magnetic field B exist, the electromagnetic force F on q, as measured by a laboratory observer, is given by Lorentz's force equation: (5-5X6-29) F=q(E + u × B). Lorentz's force equation To an observer moving with q, there is no apparent motion, and the force on q can be interpreted as caused by an electric field E, where (6-30) E, = E + ux B, we or (6-31) Hence, when a conducting circuit with contour C and surface S moves with a velocity u in a field (E, B). we use Eq. (6-31) in Eq. (6-8) to obtain (6-32) General form of Faraday's law Equation (6-32) is the general form of Faraday's law for a moving circuit in a time-varying magnetic field. The line integral on the left side is the emf induced in the moving frame of reference. The first term on the right side represents the transformer emf due to the time variation of B, and the second term represents the motional emf due to the motion of the circuit in B. If we designate the left side of Eq. (6-32) by (6-33) emf induced in circuit C measured in the moving frame, it can be proved in general that Eq. (6-32) is equivalent to Another form of Faraday's law dt (6-34) which is of the same form as Eq. (6-12). Of course, if a circuit is not in motion, y reduces to . Hence, Faraday's law that the emf induced in a closed circuit equals the negative time-rate of increase of the magnetic flux linking a ~

Answer 1

i approach this question in a different way you too follow the same way for further problems.

4S.ds dlt 沒f1 부수( -) . ) d2) dt , hwy. R.

I think it would be very helpful in understanding the problem and getting the answer as well.

Thank you

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