Please do solve for all parts. And do include all steps/diagrams as I am new to this topic
residential load:
since demand factor=50%, maximum load by each resident=0.5*20 KW=10 kW.
and DF=Sum of Individual Maximum Demands / Maximum Demand of the System
total maximum demand=(10*200/3.2)=625 kW
residential load maximum demand on its feeder=625/1.5=416.6667 kW
Business load:
since demand factor=60%, maximum load by it=0.6*200 KW=120 kW
Maximum demand=(120/1.4)=85.714 kW
business load feeder had demand=85.714/1.2=71.42833
peak demand of city substation=416.667+71.42833=488 kW
Please do solve for all parts. And do include all steps/diagrams as I am new to this topic (a) A new colony of 200 houses is being established, with each house having an average connected load of 20...
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