Question

please show step by step solution for problem J

(J) For the sleeve and bushing of problem (I) if the pressure at the mating surface is 10,260 psi what is the tensile stress in the sleeve? Tensile stress = 46,470 psi Answer Box: Enter numerical values in italics t Data Inside radius of inner member Outside radius of inner memeber 0.0000 in b 0.5000 in 0.6250 in δ= 0.0019 in E0 = 3.00E+07 psi E- 300E+07 psi Outside radius of outer memeber = Total interference Modulus of outer member = Modulus of inner member Poisson's ratio for outer member Poisson's ratio for inner member 0.27 0.27 results Co Pressure at Mating Surface: 10,260 psi Tense Stress in the Outer Member a.46,740 (I) A sleeve made of SAE 1020 hot-rolled steel is in the form of a hollow cylinder with a nominal inside diameter of 1.000 in and an outside diameter of 1.250 in. It is to be mounted on a solid steel bushing (i.e. shaft with) an FN2 force fit. What is the maximum interference between the sleeve and bushing? Note that the table for FN2 force fits uses the basic hole system and shows the standard limits in units of .001 inches. TABLE 13-4 Force and Shrink Fits (FN) Class FN1 Class FN2 Nominal size range Standard Standard limits (in) limits oHole Shaft 0-0.12 0.05 +0.25 +0.5 0.2 +0.4 +0.85 Hole Shaft 0.5 -0 +0.3 0.85 -0 +0.6 0.12-0.24 0.1 +0.3 +0.6 0.2 +0.5 +1.0 0.6 -0 +0.4 1.0 0 +0.7 0.24-0.40 0.1 +0.4 +0.75 0.4 +0.6 +1.4 0.75 -0 +0.5 1.4 -0 +1.0 0.40-0.56 0.1 +0.4 +0.8 0.5 +0.7 +1.6 0.8 -0 +0.5 1.6 -0+1 0.56-0.71 0.2 +0.4 +0.9 0.5 +0.7 +1.6 0.9 -0 +0.6 1.6 -0 +1.2 0.71-0.95 0.2 +0.5 +1.1 0.6 +0.8 +1.9 1.1 0 +0.7 1.9 -0 +1.4 0.95-1.19 0.3 +0.5 +1.2 0.6 +0.8 +1.9 1.2 -0 +0.8 1.9 -0 +1.4 1.19-1.58 0.3 +0.6 +1.3 0.8 +1.0 +2.4 1.3 -0 +0.9 2.4 -0 +1.8 1.58-1.97 0.4 +0.6 +1.4 0.8 +1.0 +2.4 1.4 -0 +1.0 24-0+1.8 Mating surface where interference occurs a 0 Sleeve Bushing Answer Box Maximum interference 0019 inch Class of Fit:FN2 Nominal Shaft Diameter: D, 1.0000 inches Standard Upper imit for Hole: SL 0.0008 inches Standard Lower limit for Hole: SL-M 0.0000 inches Standard Upper limit for Shaft: SL.s 0.0019 inches Standard Lower imit for Shaft: SLs 0.0014 inches Results Formula Mnimum Hole Diameter: D.H= 1.0000 inches Maximumhble Diameter: D·H- 1.0008 inches Minimum Shaft Diameter: D.s= 1.0014 inches Maximum Shaft Diameter: D.s# 1.0019 inches Maximum Interference0.0019 inches Minimum Interference 0.0006 inches Ds Ds+ SL Ds Ds +SL Maximum Inteference Ds-D Mnimum Interference Ds D.H 0

Answer 1

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