(3.74 f (a(0)) for all sufficiently small values ofe. If the derivative α' (0) IS very large in size, then the small change e will be magnified greatly in its effect on the root.
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6. Consider the problem of solving x/(1 +x)-0.99-0, calling its root a. Then let α (e) be the solution of x/(1 + x)-0.99 + € 0. (a) Using (3.74), estimate (e)- . (b) Calculate α(e)directly,...
please explain and do in matlab Problem 3. Consider the function f(x) e cos(2r). (1) Sketch its graph over the interval [0, m) by the following commands: (2) Using h = 0.01 π/6 in [0, π]. The comm...
please explain and do in matlab
Problem 3. Consider the function f(x) e cos(2r). (1) Sketch its graph over the interval [0, m) by the following commands: (2) Using h = 0.01 π/6 in [0, π]. The commands are: to compute the difference quotient for z And the difference quotient is: ( 6 (3) Using h-0.01 to approximate the second derivative by computing the difdifquo for in [0, π). The commands are: And the difdifquo is:
Problem 3. Consider the...
-0.2r 2.5x using the bisection method (1 point) In this problem you will approximate a solution of e Instead of solving e22.5x, you can let f(z) 027 - 2.5z and solve f(z) 0 First find a rough guess f...
-0.2r 2.5x using the bisection method (1 point) In this problem you will approximate a solution of e Instead of solving e22.5x, you can let f(z) 027 - 2.5z and solve f(z) 0 First find a rough guess for where a solution might be Evaluate f(x) at -4,-3,-2,-1,0, 1,2,3, and 4. Remember that you can make Webwork do your calculations for you! f(-4) f(-3) f(-2) f(0)- f(1) = f(2) - f(3) - f(4) Using your answers above, the Intermediate Value...
[7] 1. Consider the initial value problem (IVP) y′(t) = −y(t), y(0) = 1 The solution to this IVP ...
[7] 1. Consider the initial value problem (IVP) y′(t) = −y(t), y(0) = 1 The solution to this IVP is y(t) = e−t [1] i) Implement Euler’s method and generate an approximate solution of this IVP over the interval [0,2], using stepsize h = 0.1. (The Google sheet posted on LEARN is set up to carry out precisely this task.) Report the resulting approximation of the value y(2). [1] ii) Repeat part (ii), but use stepsize h = 0.05. Describe...
Consider a cylindrical capacitor like that shown in Fig. 24.6. Let d = rb − ra...
Consider a cylindrical capacitor like that shown in Fig. 24.6. Let d = rb − ra be the spacing between the inner and outer conductors. (a) Let the radii of the two conductors be only slightly different, so that d << ra. Show that the result derived in Example 24.4 (Section 24.1) for the capacitance of a cylindrical capacitor then reduces to Eq. (24.2), the equation for the capacitance of a parallel-plate capacitor, with A being the surface area of...
please explain and do in matlab
Problem 3. Consider the function f(x) e cos(2r). (1) Sketch its graph over the interval [0, m) by the following commands: (2) Using h = 0.01 π/6 in [0, π]. The commands are: to compute the difference quotient for z And the difference quotient is: ( 6 (3) Using h-0.01 to approximate the second derivative by computing the difdifquo for in [0, π). The commands are: And the difdifquo is:
Problem 3. Consider the...
-0.2r 2.5x using the bisection method (1 point) In this problem you will approximate a solution of e Instead of solving e22.5x, you can let f(z) 027 - 2.5z and solve f(z) 0 First find a rough guess for where a solution might be Evaluate f(x) at -4,-3,-2,-1,0, 1,2,3, and 4. Remember that you can make Webwork do your calculations for you! f(-4) f(-3) f(-2) f(0)- f(1) = f(2) - f(3) - f(4) Using your answers above, the Intermediate Value...
Consider a cylindrical capacitor like that shown in Fig. 24.6. Let d = rb − ra be the spacing between the inner and outer conductors. (a) Let the radii of the two conductors be only slightly different, so that d << ra. Show that the result derived in Example 24.4 (Section 24.1) for the capacitance of a cylindrical capacitor then reduces to Eq. (24.2), the equation for the capacitance of a parallel-plate capacitor, with A being the surface area of...
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