LM317 Design Calculation
Vout = 6V
Vin = 9V
Say, R2=1KΩ = 1000Ω
Then,
Then, R1 = 263Ω
Therefore, with R1=263Ω and R2=1KΩ, We get Vout = 6V.
For LED to properly lit, and Vf=3V, If = 10 mamp,
The resistance R3 = R3= VI=6000 mV10 mamp=600Ω
For the circuit shown below, design the values of R1 and R2 that will cause Vout-6 Vif VIv-9 V. If the resistors you chose have a tolerance of 1 %, what is the maximum and minimum values of Vout? Des...
The circuit shown in the figure below contains three resistors (R1, R2, and R3) and three batteries (VA, VB, and Vc). The resistor values are: R1=2 Ohms, R =R3=4 Ohms, and the battery voltages are VA=25 V, V8=15 V, and Vc=20 V. When the circuit is connected, what will be the power dissipated by R1? VC + R1 ş VA + - + Vв R2 ma R3 1.25 W 2.0 W 12.5 W 6.25 W 8.13 W
C.la For the circuit of Figure 1, choose values for resistors R1, R2, and R3(all resistances must be greater than one Kilo ohm). Given that the voltage source Vs1 = 8V and Vs2 = 10V determine the output voltage Vout. C.1b For the same resistor values Ri, R2, and Rs you chose in part C.la Given that the voltage source Vsi = 8V and Vs2 = 10V, use Figure 2(a) to determine the output voltage Vout/ and Figure 2(b) to determine the output voltage Vout2. Discussion:...
(1) The resistors in the circuit below have the following values: R1 = 8.00 Ω, R2 = 7.00 Ω, and R3 = 3.00 Ω. The two batteries each have a voltage of 5.00 V. (a) Find the current in through R3. (b) How much power do the batteries deliver to R3? (2) Using the exact exponential treatment, find how much time is required to discharge a 242-µF capacitor through a 495-Ω resistor down to 1.00% of its original voltage. 3....
Consider the circuit shown in (Figure 1). The batteries have emfs of ε1 = 9.0 V and ε2 = 12.0 V and the resistors have values of R1 = 27Ω, R2 = 60 Ω, and R3 = 33 Ω. Determine the magnitudes of the currents in each resistor shown in the figure. Ignore internal resistance of the batteries. Determine the directions of the currents in each resistor. Ignore internal resistance of the batteries.