Question

Find the new weight using pack propagation when the net show below is presented the input pattern (-1 1 -1) and the desired output is _1 using learning rate 0.1and tan sigmoid activation function the bias is set to 1 moment rate is 0.5

Find the new weights using back-propagation when the net shown below is presented the input pattern (-11-1) and the desired output is -1. Use a learning rate of 0.1 and tan-sigmoid activation function. The bias is set to 1, and momentum rate is 0.5, bias 0.1 bias 0.2 0.1 X1 0.2 7.1 .2 0.1 0.1 0.1 X2 0. 0.1 bias Scanned With CardScmner

Answer 1

SOLUTION:

Solulicn. ous 5s bias 0 34 Ö.2 as - o leorning nate Jaton . Seall wetahts blw 24 +2-4 i- Totol num bem inPuts o neuven wher Aelvabon Calcdate actualof nes LH0n3 İn Hidden Uw puts of neuvon J. in the hidden leye

s'9meid s the Sigmoid Auon Colulak the ac in he output putsf the nea whee m- no in neuron m es 0 Cal lak Evver e neuvonS the whseex(P)- Juk (P)- Y(P) Collulak weight Coecbons uylate the weights ot the ouut nu?n5 neu rons in Hidden layes eyv yradil b) Calaale Culak weight Lovecbons Pdate thewhsathidden neuvon s to slep amd nepeat the lenom s Sabsed- teYatons sunbl Scle ded eS

3 34 160 Jy. teo- 2 3449 +3499 5 I LO"(-0.2) 2 2-214 nowrhe Ou

no the actual -의p-of-neuvon. ts.--determined at in-the obria 6 0-9162 Snte desired output vem -1-0.5218 35218

Now we hove t traun the weights To updale the weighth und threshlds level i 61 we eagak 4ke Cum vove neuuton 0-5 lI 10.5218 leasning nale 39o-037

Next, we Calulalk Egradents r neu on in the hiddenlaycv and 5 Uw) 042S5 (04 25 5 0 0092 e (I -034q 구) (0-1 -0 so (I0 50 EO-o013 (041) (-1) to·。0928) (1) (-0.00928) (о. )--(-1)(-000913)-- リ(-0 . 0 000 9 28 -0-000 9 28 --o:000928 o.ooo9a8 し13-J4 4, - o o028

-0003q (-o-ooq39) --o.ooo 9 3 ๆ (m) l) 一0.000939 づ· ス 스19-5 = 5 o.ooo 939 (-o.oo939Js イ·χ3°S5 ס (0-1) (1) .15. (。»)(-') dW35 eo.。。939) 一0.000939 - At last we update wights omd threshold 15 -0-1 + (-0.000939) = 0.011061 ο : l + Co.ooo939) = 0-1009 39 し035 + Δω35 D35 o.、一0.000918 = 0.0990 t 0 . 1-0, bo 09 39 D. 9906 1 toi pyocess hold be nepeakd untl the Sum Suared enovS-is-less than 0:00

netwok afte, updahing we Neuval B:as 3 5 ω34-0.200928 6-199 on з't 0 lo0 439 s 0loo (oo3 LU e0.906 dated ทุew ^wei are AIl e above

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