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Problem 2 [2 4 6 81 Let A 1 3 0 5; L1 1 6 3 a) Find a basis for the nullspace of A b) Find the basis for the rowspace of A c)
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Consider the matrix A-1 3 0 5 Convert reduced row echelon form of a matrix. applying the row operation 0 1 -3 1 01-3 1 The ab

12r1 +4r2 + 6r3 +840 Here, 2 equations and 4 variables so 4-2 variables will be free variables These variables can take any v

0-3 1 Therefore, the row space has a basis is as follows (2 4 6 8],[0 1 -3 1] The range space has a basis is as follows 21 [4

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Problem 2 [2 4 6 81 Let A 1 3 0 5; L1 1 6 3 a) Find a basis for the nullspace of A b) Find the basis for the rowspace of A c) Find the basis for the range of A that consists of column vectors of...
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