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5. Consider the following two scenarios: I. 45.0 mL of 0.80 M strontium acetate is mixed with 70.0 mL of 0.60 M potassium II

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Answer #1

I) there is no reaction takes place here . so answer NR

II ) reaction will takes place

a) balanced equation :

Sr(CH3COO)2 (aq) + Na2SO4(aq) ----------------> SrSO4 (s) + 2 CH3COONa (aq)

b)

moles of Sr(CH3COO)2 = 45 x 0.80 / 1000 = 0.036

moles of Na2SO4   = 70 x 0.60 / 1000 = 0.042

limiting reagent is Sr(CH3COO)2 . so product is based on limiting reagent

so moles of SrSO4 formed = 0.036

SrSO4 molar mass = 183.68 g / moles

mass of SrSO4 = moles x molar mass

                         = 0.036 x 183.68

                       = 6.61 g

mass of solid = 6.61 g

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5. Consider the following two scenarios: I. 45.0 mL of 0.80 M strontium acetate is mixed with 70.0 mL of 0.60 M potassium II 45.0 mL of 0.80 M strontium chloride is mixed with 70.0 mL of 0.60 M sodiu...
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