Why are polyaniline nanofibres more porous and have higher
surface area than thin film
polyaniline?
Polyaniline nanofibers are more porous and have higher surface area than film polyaniline because of small fiber diameters which is 100-200 nm and are amphiphilic in nature.
These polyaniline nanofibers have cylindrical morphology that form more porous structures and as their diameter are in nanometers have larger surface area/unit mass which permits the increase in the surface activities whereas thin film polyaniline are in highly agglomerate form and large in size (diameters).
Hence less porous and have less surface area.
Why are polyaniline nanofibres more porous and have higher surface area than thin film polyaniline?
Why use aluminum thin film as the positive electrode current collector and copper thin film as the negative electrode current collector?
Why does saltwater have more carbonates and therefore higher alkalinity than freshwater?
12. For surface plasmon resonance (SPR), answer the following questions: a) Describe the experimental set-up of the Kretschmann configuration to excite a surface plasmon in a metal thin film? b) Draw the experimental set-up, how does the laser beam interact with the metal thin film, what is its polarization etc. label everything clearly c) For the case of Gold thin film with ε--10 with air as the dielectric medium ε-1, if the prism has an index of refraction n-1.6 at...
12. For surface plasmon resonance (SPR), answer the following questions a) Describe the experimental set-up of the Kretschmann configuration to excite a surface plasmon in a metal thin film? b) Draw the experimental set-up, how does the laser beam interact with the metal thin film, what is its polarization etc. label everything clearly. c) For the case of Gold thin film with ε :10 with air as the dielectric medium ε-1, if the prism has an index of refraction n-1.6...
When white light illuminates a thin film normal to the surface, it strongly reflects both blue light (500 nm in air) and red light (700 nm in air) as shown in the figure below. White light Blue and red are reflected Air Film Water 1) Calculate the minimum thickness of the film if it has an index of refraction of 1.35 and it "floats" on water with n = 1.33. (Express your answer to two significant figures.) 135 nm Submit
Monochromatic light of wavelength X-89.1um is shone at normal incidence through a thin film of thickness t resting atop a fully reflective surface. The film has an index of refraction of n film 1.5 What is the smallest thickness t (in ?m) the film could have to get constructive interference?
Consider the following thin film situation where light impinges on a surface formed by air and water with a thickness t as shown. Which of the following set of thicknesses will result in maximizing reflection of light having a frequency of 354 x 104 Hz? n 1.00 n 1.30 n 1.50
In our study of thin film interference we have seen that when light strikes a surface with a different index of refraction the incident light splits into 2 reflected beams and 2 refracted beams. The total phase difference between any two interference. This will to the two general cases described below. For each case give several applications of this situation adjacent beams can lead to either constructive or destructive 17 Case I: Beams 1 & 2 interfere constructively (maximum reflection.,)...
The reflection of light from the thin film of thickness t as shown in the figure appears violet (400nm) when viewed from above. This means the two rays reflecting off of the two surfaces interfere constructively. t is the minimum thickness. The dark grey material has a higher index of refraction than the light grey with the white being air. For what minimum thickness relative to t would it need to be for the film to now appear red (700nm)...
Question 5: How would dust and oil on the glass plates affect the results? EXPERIMENT 10 THIN FILM INTERFERENCE Light from a monochromatic source is shined downward on two glass plates that are separated at one end by a hair. Light that is reflected from the top and bottom surfaces of the wedge-shaped thin film of air undergoes interference, and a series of dark and light lines are seen. By counting the number of dark or light lines over a...