c. There exists a piecewise continuous and exponential order function that L[f(t)] = 3. True False Reason c. There exists a piecewise continuous and exponential order function that L[f(t)] = 3....
MACT 2141 Problem 6. (5 pts each) True or False (Cirele one and state your reason a. If J(t) is a solution of the DE:'+( tA 2019 4y5, then so is the function Reason: True False f and g be two functions, such that F(s) Lf ()) and G(s) Lig()) are defined on (0, oo). If f(t) S g(t) for all t 2 0, then F(s) S G(s) for all s >0. True False Reason: c. There exists a piecewise...
6. (5 pts each) True or False (Cirele one and state your em) reason) a IE f(e) is a solution of the DE: y+(i ty + 4y 5, then so is the uo sit)--f(t) Reason: True b. Let f and g be two functions, such that F(s) Lif(t) and G(s)ig defined on (0, oo). If f(t) s g(t) for all t 20, then F(o) s G(o) for alls True Fais Reason: c. There exists a piecewise continuous and exponential order...
23 43 Problem 6. (5 pts each) True or False (Circle one and state your seaon) If t) is a solution of the DE: "+(t-t)y+Ay- 5, then so is the f Reason: rue Fa b. Let f and g be two functions, such that F(s)L0) and Go)-Li defined on (0, oo). If f(t) S 9(t) for allt 2 0, then F(o) S Glo) for als True F Reason: c. There exists a piecewise continuous and ex that LIf(0)]-3 exponential order...
6) True or False? (justify your answers a) I f ft) is piece wise Continuous on [goo) and of exponential order and L [f(t)] = FC), then L [ S t f (G) I TE F(S) ? S 6) The Function F(s) = 1 is the Laplace transform of a function that is a piecewise continuous on [o,oo) and of exponential order?
The Laplace transform of the piecewise continuous function $4, 0<t<3 f(t) is given by 2, t> 3 1 L{f} (1 – 2e-st), 8 >0. S None of them L{f} = (1 – 3e®), s>0. 2 L{f} (3 - e-), 8 >0. S 2 L{f} (2-est), s >0. S
The Laplace transform of the piecewise continuous function $4, 0<t<3 f(t) is given by 2, t> 3 1 L{f} (1 – 2e-st), 8 >0. S None of them L{f} = (1 – 3e®), s>0. 2 L{f} (3 - e-), 8 >0. S 2 L{f} (2-est), s >0. S
Let g be a piecewise continuous function of exponential order on [0, 0). Use the Laplace transform to solve the following initial value problem. dy -(t) + 2y(t) = g(t), y(0) = 0, dy (0) = 1. Express your answer by using the convolution operator *.
Question 9 3 pts The Laplace transform of the piecewise continuous function 4, 0<t <3 f(t) is given by t> 3 (2, L{f} = { (1 – 3e-*), s>0. O 2 L{f} (2 - e-st), 8 >0. 2 L{f} = (3 - e-st), s >0. O None of them 1 L{f} (1 – 2e -st), s >0.
Rewrite the following piecewise continuous function f (t) in terms of the unit-step function. Then find its Laplace transform f(t) =
Rewrite the following piecewise continuous function f (t) in terms of the unit-step function. Then find its Laplace transform f(t) =
1. Determine whether the statement is true or false. If false, explain why and correct the statement (T/FIf)exists, then lim ()f) o( T / F ) If f is continuous, then lim f(x) = f(r) (TFo)-L, then lim f(x)- lim F(x) "( T / F ) If lim -f(x)s lim. f(x) L, then lim f(x)s 1. "(T/F) lim. In x -oo . (T/F) lim0 ·(T / F ) The derivative f' (a) is the instantaneous rate of change of y...