An administrator in the Department of Power and Electrical Engineering needs to upgrade computers for the Department. She wants to know what sort of computer system employees prefer. She has three available choices: windows, mac, linux or no preference. The observed data is shown in table below:
Type of Computer | Observed |
Windows | 20 |
Mac | 60 |
Linux | 20 |
Using the chi-square test of significance:
a) State the hypotheses
b) Test the hypothesis or theory that an equal percentage of the
employees prefers each type of computer system.
Chi square test of goodness of fit.
Null hypothesis (H0) : Pwin = PMac = PLinux
Alternate hypothesis (Ha:) : Proportion not same
Type of computer | observed Frequency(Oi) | Expected Frequency(Ei) | (Oi - Ei)^2 | ((Oi-Ei)^2)/Ei |
Window | 20 | 33.33 | 177.8 | 5.33 |
Mac | 60 | 33.33 | 711.1 | 21.33 |
Linux | 20 | 33.33 | 177.8 | 5.33 |
Total | 100 | 32.00 |
Chi Square value = 5.33+21.33+5.33 = 32.00 |
Here P value =0.00000011
Here p value < 0.01 so we reject Ho.
So we can conclude that proportion not same for employee prefers each type of computer system.
An administrator in the Department of Power and Electrical Engineering needs to upgrade computers for the Department. She wants to know what sort of computer system employees prefer. She has three ava...