Question

fimd answr using TI 84

M m,s milk chocolate are a popular chocolate candy with six different colors (30% brown, 20% yellow, 20% red, 10% orange, 10% green, 10% blue). A sample of 200 people recorded the colors of m m's in the table below. Brown is 67 yellow is 39 red is 45 orange is 15 reen is 17 blue is 17 Test at a significant level of 5% that the random variable follows a certain distribution

Answer 1

H0: Random variable follows certain distribution

H1: Random variable does not follow certain distribution

Using TI-84 calculator.

First find expected frequency

E = n * Pi               Where n = 200

Degrees of freedom = Number of expected -1 = 6 - 1 = 5

Observed	Expected=n*Pi
67	= 200 * 0.30 = 60
39	=200*0.2 = 40
45	=200*0.2 = 40
15	= 200* 0.1 = 20
17	= 200* 0.1 = 20
17	= 200* 0.1 = 20

Press Stat>Press enter

Enter Observed values in L1 and Expected in L2

Press Stat>Highlight TESTS>Select X2GOF-Test>

Obseved: Press 2nd 1

Expected: Press 2nd 2

df : 5

Press enter

We got following values:

                   (Round to 3 decimal)

23.617

P = 0.6058            (Round to 4 decimal)

Here alpha = level of significance = 0.05

P value > alpha

So we fail to reject null hypothesis H0.