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Many consumers pay careful atention to contents on packaged foods when making purchases, so stated nutri- that a random sampl

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a) It is correct to choose one sample t-test because the sample is taken from a large population and the plot also show that the distribution is approximately normal and hence assumed as normal distribution but the sample size is less than 30 so t- distribution is assumed .

b) No, because the box plot appears a normally distributed from naked eye view and also the median is around 240 so, we cannot say that the mean differs from 240.

c) Since the mean is calculated as

1

z = 244.33z = 244.33

and Sample standard deviation is calculated as

N -1 N-1 -(255-244.33333333333)2(233 -244.33333333333)2 12-1 1686.6666666667 153.33333333333 s : .. 153.33333333333 12.382783

The Hypotheses are

Ho:μ=240

Ha : μ 240

Significance level is assumed as 0.05 since it is not given in ques

rejection region:

Reject Ho if |T| >t 0.05, 11 =2.20 , where 11= degree of freedom =n-1=12-1=11

Test statistic:

x-μ 1.21 V12 7t

P-value:

P-value associated with t Score calculated above as

0.1<p-value<0.5

Conclusion:

Since T< t 0.05,11 =2.20 and P-value > 0.05 hence we fail to reject the null hypothesis and conclude that there is insufficient evidence to support the claim that mean differs from 240 at 0.05 level of significance.

T-table used for calculation as

Numbers in each row of the table are values on a t-distribution with (df) degrees of freedom for selected right-tail (greater

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