Question

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B: Scrateh papers are not allowed during the exam. An ed and used as seratch but will not be considered for grading y sheet of the booklet can be Four polarizing sheets are stacked as follows: the first is at 10.0 clockwise the vertical, the second is at an angle of 10.0° counterclockwise (CCw) with the W) with cal, the third is at 40.0° CW with the vertical, and the fourth is horizontal. The incident light n intensity lo 500 W/m2 Calculate 14, the transmitted intensity by the system if the incident light lo is unpolarized? the incident light lo is vertically polarized? For the remainder of the problem assume that 10-500 W/㎡ and is vertically polarized. Calculate the transmitted intensity if the second polarizer is removed. What would be the transmitted intensity if the second and the third polarizer are 以- exchanged? If the second polarizer is removed, what should be the angle (with the vertical) of the third polarizer so that maximum intensity can be transmitted through the system? Calculate this maximum intensity Light is incident on air-water interface at the Brewster angle θΒ of that interface an reflects toward the original system of 4 polarizers. Calculate the fraction of the incident light u is transmitted by the system. cindex of

Answer 1

g° Lo I 2 500 11 c0316 1,~ : 2o whuu 25o Co (30 wl 2 13 = マ30.75

co,82 ( 50. 230.75 13 = 3g1 20 w กา mow 13 ,816 c o チー = 50 whuu 91.20 Co (50. I43.68

, 10 , 90 T. whit 610 T, 5oo Cos 10 484 9m2 mow 484 93 Co (o wn2 2428 195 w 叨 mow T3428 195 Cos (50

mow I. T4176 91 5) I: I: Io I0 whuu6 whrt 4 に : 500 cos3(10°

twhuu co ,2130.) 13 484-33 = ta = 363.69 wl.m2 whusu c.,3150 363.6g 丁 T3= 150.36 i go d ) I3 I 1

TL = To cone (0,82(LO, 五ー 500 T2 484 92 Co(3 cos? (50) 13 363.69 w2 150.26 3 4 whru 150 26 Cos t8o 14= 4.53 チ