A. For D1:
Profit Maximisation problem = PXQ1 - C(Q1)
= q1 x ( 1 + s - q1-q2) - w(q1) - (e1)^2
Profit Maximisation for D2 = PXQ2 - C(Q2)
= q2 x (1+s -q1-q2) - w(q2) - (e2)^2
B. First Order conditions will be:
For D1: d/dq1 [q1 x(1+s-q1-q2) - wq1 - (e1)^2]
Differentiate the condition with respect to q1
= (1+s-q1-q2) - w : first order differentiation
equate the equation to 0
1+s-q1-q2 - w = 0
= w = 1+s+q1+q2
Follow the same for D2:
d/dq2 [q2x(1+s-q1-q2) - wq2 - (e2)^2]
= (1+s-q1-q2) - w : first order differentiation for D2
equate it with 0
1+s-q1-q2=w
this implies for profit to maximise the wage should be equal to 1+s+e1+e2
C. At equilibrium : MR=MC
In case of D1: MR1 = d/dq1( q1 x (1+s-q1-q2)) = 1+s-q1-q2
MC1 = d/dq1 ( wq1+(e1)^2)= w
This implies that MR1=MC1 = w= 1+s-q1-q2
Similarly in the case of D2 :
MR2=MC2=w=1+s-q1-q2
This means for equilibrium: w = 1+s-q1-q2 = 1+e1+e2-q1-q2 for booth D1 and D2.
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