4) PW = -$1000 + 3000(P/F,10%,3)
4) PW = -$1000 + 3000(P/F,10%,3) Single payment present (P/F, i,N)worth factor Single payment present (P/F, i,N)wo...
Periods Compound Present Capital Compound Present Amount Worth Sinking Recovery Amount Worth Factor Factor Fund Factor Factor Factor Factor Find F Given Find P Given Find A Given Find A Given Find F Given Find P Given Р F F Р А A F/P PIF A/F AIP FIA PIA N 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30...
319 71% 120:12 3. Present worth (PW) 4 pts A wind farm in Victoria consists of rated wind power of [RP] MW, with a capacity factor of [CF]%. The capital cost is about $[cc]/kW rated power. The electricity produced over one year is sold at $[LCOE]/kWh. The farm needs to spend about [OM]% of the capital cost for maintenance every year and at the end of [n] years it is expected to have a salvage value of [S]% of the...
1 year= $3000 2 year= $3000 3 year= $6000 4 year= $9000 5 year= $12000 6 year= $15000 X Problem 6-2 (algorithmic) Question Help O $10,000 OOO Years 0 ! 53.00 53.000 $.000 $2,000 $12.000 315.000 Click the icon to view the interest factors for discrete compounding when = 7% per year. i More Info The equivalent annual worth is S . (Round to the nearest dollar) Single Payment Compound Present Amount Worth Factor Factor (F/P.I, NJ (P/F, I, NJ...
The single payment compound amount factor is used to find the value of sum and is written as (F/P, i, n) O present...recurring O present.future O future...recurring O future...present
Consider the accompanying cash flow diagram. Compute the equivalent annual worth at i= 10 % 6. $5,000 $6,000 $4,000 $3,000 2 4 56 Years $3,000 Click the icon to view the interest factors for discrete compounding when i 10% per year The equivalent annual worth is $ (Round to the nearest dollar.) 8: More Info Equal Payment Series Single Payment Gradient Series Gradient Present Compound Present Compound Amount Sinking Present Capital Recovery Gradient Worth Fund Worth Uniform Amount Factor Factor...
Consider the independent investment projects in the table below. Compute the project worth of each project at the end of six years with variable MARRs as follows: 10% for n = 0 to n= 3 and 15% for n = 4 to n=6. B Click the icon to view the information about the independent investment projects. Click the icon to view the interest factors for discrete compounding when MARR = 10% per year. Click the icon to view the interest...
5.8) Compute the present value, P, for the following cash flows. 3000 2000 1000 8 i 129 Use a geometric gradient formula to compute the Present value. P. for the following cash flows. 266.20 159 5 24
x=3000 P 1.2 = Calculate the present worth for the cash flows with different specified periodic interest rates. The cash flow diagram is given: Note that X is the last digit of your University ID and its in 1000. For example, if student ID is 3, the value of X is $ 3000. PE? 8% Comp annually 9% Compounded quarterly 12% compounded monthly $2000 + X $2000 + X $2000 + X
3000 3000 3000 3000 3000 2250 1688 1266 949 712 534 0 1 2 3 4 5 6 7 8 9 10 Solve without Using excel/Matlab. solve using GIVEN formulas whenever APPLICABLE. ((Do not try to solve by assuming each cash flow as a single cash flow at its corresponding year)) Problem 3 [20p]: A cash flow the attached diagram (where years). If the interest rate is 18% calculate the uniform series equivale A cash flow over 10 years is...
Please Calculate the expected PW value for building and widening a two-lane bridge. Will rate highly. A bridge is to be constructed now as part of a new road. An analysis has shown that traffic density on the new road will justify a two-lane bridge at the present time. Because of uncertainty regarding future use of the road, the time at which an extra two lanes will be required is currently being studied. The estimated probabilities of having to widen...