Find the periodie cubie spline sp(x) passing through the 3 points (^j, yj) given by (0, 1), (2,1), and (3,2). Then eval...
Problem 3. (8 points) Given that the interpolation polynomial of the points (-3,2), (-2,1),(-1,-1), (0,1), (1,0), (2,0), (3, 1) is 191 13 5 781 , 53 Q(x) = -3602 + 30++ Find a polynomial curve passing through these seven points and additionally the point (4,0). Write your polynomial in standard form anx" +...+212 +00 +1. 360" + en
Given the data points (-3,5),(-2,5),(-1,3), (0, 1) (a) Find the interpolating polynomial passing through these points. (b) Using your polynomial from (a), evaluate P(1). (c) This polynomial interpolates the function f(x) = 24. Find an upper bound for the approximation in part (b).
5. (a) The natural spline S(a) passing through the n+ points is a collection of n cubic functions S,(x) defined in the n intervals x, Sxx Suppose that all the points are equally spaced, with uniform point spacing h=5m-x, for jso,1,..,,n. Ifthe symbols M,, 0, represent the second derivatives of the spline at cach of the mesh points, show that in each intervl-.R-1 For the natural cubic spline (for which M, O and M-=0 ), show that the moments M...
Find an equation of the plane passing through the given points. (3, 4, –4), (3, -4,4), (-3, -4, -4) Tx - 69 - 7z - 25 = 0 x
matlab 2) Plots the individual points with "star" marks b) Fisa cubie spline to the data use "o" marks c) Fits a 5th order polynomial use "x" marks 3) MATLAB contains functions to calculate the natural logarithm (log), the logarithm to the base 10 (log 10), and the logarithm to the buse 2 (log2). However, if you want to find a logarithm to another base for example, base - you'll have to do the math yourself with the formula log)(x)...
x (x) 3 Find a formula for the exponential function passing through the points (-3, -) and (1,15) 125 y =
Find an equation of the plane passing through the given points. (3, 4, -4), (3, -4,4), (-3, -4, -4)
Find an equation of the plane passing through the given points. (3, 4, -4), (3, -4,4), (-3, -4, -4) 7x - 6y - 7z - 25 = 0x
Find an equation of the plane passing through the given points. (3, 4, -4), (3, -4,4), (-3, -4,-4) 7x -6y - 72 – 25 = 0x
1. Find the quadratic spline through the points {(0,0),(1,3),(2,2),(3,4)} which is differentiable at each interior point and has slope zero at the origin. 2. Compute a second quadratic spine through the same points replacing the zero slope condition with the `not-a-knot' condition that the spline be twice differentiable between 0 and 2.