Question

Using MiniTab, create a Probablity Prob Graph with this:

TABLE 6E.6 2008 NFL Quarterback Rating Data Yards per Rating Team AttemptPoints Player 105.5 SD 8.39 Philip Rivers ChadPennington MIA 7.67 97.4 7.66 96.9 Kurt Warner ARI NO 7.98 96.2 Drew Brees 95 7.21 Peyton Manning IND 7.53 93.8 Aaron Rodgers GB HOU 8.01 92.7 Tuat DAL766 Jeff Garcia 7.21 90.2 NE blat 7.16 89.4 Matt Ryan 7.93 87.7 haun 7.10 87.5 Seneca Wallace 6.33 NYG6.76 86.4 Manning Donovan McNabb 6.86 86.4 Cutler 7.35 Trent Edwards BUF 7.22 85.4 JakeDelhommeCAR 7.9484.7 Jason Campbell WAS 6.41 843 DavidGarrardJAC 81.7 Brett Favre 6.65 81 BAL 6.94 80 Kerry Collins 80.2 6.45 BenRoethlisberger PIT7.0480.1 CHI Kyle 6.39 79.6 Orton JaMarcus Russell 6.5877.1 OAK Tyler Thigpen KC 73.7 7.17 Gus Freotte MIN ET 6.3426 DanOrlovsky MarcBulger FitzpatrickCIN DerekAnderson

Answer 1

a) Using MINITAB, the regression equation for the given data is as shown below: Regression Analysis: Rating points versus Yards per Attempt Analysis of Variance DF Adj SS Adj MS F-Value P-Value Source Regression 1 1672.47 1724761.41 0.000 Yards per Attempt 1 167247 167247 6141 .000 Error 30 817.06 27.24 Lack-of-Fit 28 79041 28.23 2.12 0.371 Pure Error 2 26.64 13.32 Total 31 2489.52 Model Summary 5.21874 67.186 66.096 62.26 Coefficients Coef SE Coef T-Value P-Value VIF Term 57 0.128 Constant 14.20 9.06 Yards per Attempt 10.09 1.29 7.840.000 1.00 Regression Equation Rating points14.2010.09 Yards per Attempt From the above output, the regression equation is, у 14.20-10.09х

From MINITAB output, the slope is β 10.09 The estimate of intercept is β,-14.20 The estimate of σ is σ-MSE-2724 b) The estimate of the mean rating when x 6.2 is E(Y6.2)-o+B, (6.2) 14.20+10.09(6.2) -76.758 The change in the mean rating associated with a decrease of one yard per attempt is, -10.09(-1) 10.09

d) The change in the mean rating associated with the change of Ar yards per attempt is Therefore to increase the mean rating by 9 points there must be generated an increase in he average yards per attemptby 10.09 10.09 The fitted value ofy when x- 7.21 is, 14.20 + 10.09(721) 86.9489 У There are two observations in the table associated withx-7.21, namely y-95 and 90.2 The corresponding residuals are: y-y-95-86.9489 8.05 1 1 e And e = y-y-90.2-869489-3 .25 1 1