Question

KINDLY Describe the approach (in plain English) used to completing the coding below and explain the major decisions made in designing the program.

As part of your explanation, be sure to identify the Java constructs you used that are specific and relevant to the program below. Depending on the program, these may include the mechanisms for output, input, selection statements, loops, methods, and so forth.

***********BEGINNING OF CODE***************

import java.util.*;

public class CountOccurances{

public static void main(String[] args) {

Scanner userIn = new Scanner(System.in);

int arr[] = new int[7];

System.out.print("Please enter 7 integers: ");

for(int i=0; i<7; i++){

arr[i] = userIn.nextInt();

}

System.out.println("Count Occurrences in Seven Integers Using Java Single Dimension Arrays Instructions");

for(int i=0; i<7; i++){

int c = 0;

for(int j=0; j<7; j++){

if(arr[i]==arr[j])

c++;

}

System.out.println(arr[i]+":"+c);

}

}

}

***********END OF CODE***************

Answer 1

The code is basically ask user to enter 7 digit and store them in an array and then count the occurance of each digit in the array and print the occurance if each digit in array .

import java.util.*;

public class Main{

public static void main(String[] args) {
//Scanner is use to take input from user
Scanner userIn = new Scanner(System.in);
//initialized an array of 7 integers
int arr[] = new int[7];
//ask user to enter 7 numbers
System.out.print("Please enter 7 integers: ");

for(int i=0; i<7; i++){
//store the value in array
arr[i] = userIn.nextInt();

}

System.out.println("Count Occurrences in Seven Integers Using Java Single Dimension Arrays Instructions");
//check for occurance of each number in array
//outer loops to points to an element at i th position
for(int i=0; i<7; i++){

int c = 0;
//inner loops for comparing with other values
for(int j=0; j<7; j++){

if(arr[i]==arr[j])

c++;

}
//print the result
System.out.println(arr[i]+":"+c);

}

}
}