Question

First use (20) in Section 6.4.

y'' +

1 − 2a
x

y' +

leftparen1.gif

b2c2x2c − 2 +

a2 − p2c2
x2
rightparen1.gif

y = 0,    p ≥ 0    (20)

Express the general solution of the given differential equation in terms of Bessel functions. Then use (26) and (27)

J1/2(x) =
sqrt4a.gif
2
πx
sin(x)
     (26)

cleardot.gif

J−1/2(x) =
sqrt4a.gif
2
πx
cos(x)
     (27)

to express the general solution in terms of elementary functions. (The definitions of various Bessel functions are given here.)

y'' + y = 0

y(x) =

C1
sqrt1a.gif x

sin(x) +

C2
sqrt1a.gif x

cos(x)y(x) =

C1
sqrt1a.gif x

sin(2x) +

C2
sqrt1a.gif x

cos(2x)     y(x) =

C1
x

sin(x) +

C2
x

cos(x)

y(x) = C1 sin(2x) + C2 cos(2x)

y(x) = C1 sin(x) + C2 cos(x)

First use (20) in Section 6.4 a2 - p2c2 Express the general solution of the given differential equation in terms of Bessel fu










First use (20) in Section 6.4 a2 - p2c2 Express the general solution of the given differential equation in terms of Bessel functions. Then use (26) and (27) 2 x sin(x) (26) ไม่2(x) J-1/2(x) 1/-cos(x) (27) = to express the general solution in terms of elementary functions. (The definitions of various Bessel functions are given here.) o y(x)sin(x)cos(x) Xx o y(x)sin (2x) cos(2x) Xx o x)-C1 sin(2x) C2 cos(2x) o yx)-C1 sinx)C2 cos(x)
0 0
Add a comment Improve this question Transcribed image text
Answer #1

2C 一(2) 12 LC- . Sduthn LS

Add a comment
Know the answer?
Add Answer to:
First use (20) in Section 6.4. y'' + 1 − 2a x y' + b2c2x2c − 2 + a2 − p2c2 x2...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
Active Questions
ADVERTISEMENT