Question

12 Question (1point) e See page 224 1st attempt See Periodic Table See Hint Use MO theory to determine the bond order for Be 2 Choose one: OBond Order 1/2 O Bond Order = 0 O Bond Order = -1/2 O Bond Order 2 O Bond Order =-1

Answer 1

σ and σ* orbital can have maximum of 2 electrons

π and π* orbital can have maximum of 4 electrons

1 Be atom have 4 electrons

Here, number of Be is 2

so, total number of electrons in Be2 is 8

Since charge is -1

Total number of electron = 9

So, total number of electrons to fill is 9

order of filling of orbitals is:

σ1s σ*1s σ2s σ*2s π2p σ2p π*2p σ*2p

Lets fill the orbital

the filled orbital is σ1s2 σ*1s2 σ2s2 σ*2s2 π2p1

Number of electron in bonding orbital = 5

Number of electron in Anti bonding orbital = 4

Bond Order = 0.5*(Number of electron in bonding orbital - Number of electron in Anti bonding orbital)

= 0.5*(5 - 4)

= 0.5

Answer: option 1