Question

(to 2 decimals)

Answer 1

a)

SE =s/$\sqrt{n}$

= 6/

V40

= 0.9487

Test statistic is given by:

t = (14.15-15)/0.9487

= - 0.8960

So,

t = - 0.90

(b)

ndf = n - 1 = 40 - 1 = 39

By Technology,p - value = 0.3736

So,

P - Value is between 0.10 to 0.50

(c)
P - value is greater than $\alpha$. Fail to reject H0.

(d)

$\alpha$ = 0.05

ndf = 39

From Table, critical values of t = $\pm$ 2.0227

Reject H0 if t is less than - 2.0227 or t is greater than 2.0227.

t is less than 2.0227. Fail to reject H0.

Correct option:

No